1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
timama [110]
3 years ago
8

2. The speaker argues that more data allow us to see new things. Think about your favorite hobby—skateboarding, listening to mus

ic, or whatever you most enjoy doing. What kinds of insights could big data provide about your hobby? How might these insights make things better for you? Are there any ways that big data could make your hobby worse? HELPPP MY FAVORITE HOBBY IS MUSIC
Engineering
2 answers:
taurus [48]3 years ago
5 0

Answer:

If we have more data or information when it comes to listening to music, we can easily find out who made the song or then the song was released or we can see when that songwriter will release a new hit.

Explanation:

m_a_m_a [10]3 years ago
5 0

Answer:

Explanation: if we had more information when we listen to music like the name of the singer or the writer or the name of the song we can easily find out who made the song when they release a new song

You might be interested in
An inductor (L = 400 mH), a capacitor (C = 4.43 µF), and a resistor (R = 500 Ω) are connected in series. A 44.0-Hz AC generator
MakcuM [25]

Answer:

(A) Maximum voltage will be equal to 333.194 volt

(B) Current will be leading by an angle 54.70

Explanation:

We have given maximum current in the circuit i_m=385mA=385\times 10^{-3}A=0.385A

Inductance of the inductor L=400mH=400\times 10^{-3}h=0.4H

Capacitance C=4.43\mu F=4.43\times 10^{-3}F

Frequency is given f = 44 Hz

Resistance R = 500 ohm

Inductive reactance will be x_l=\omega L=2\times 3.14\times 44\times 0.4=110.528ohm

Capacitive reactance will be equal to X_C=\frac{1}{\omega C}=\frac{1}{2\times 3.14\times 44\times 4.43\times 10^{-6}}=816.82ohm

Impedance of the circuit will be Z=\sqrt{R^2+(X_C-X_L)^2}=\sqrt{500^2+(816.92-110.52)^2}=865.44ohm

So maximum voltage will be \Delta V_{max}=0.385\times 865.44=333.194volt

(B) Phase difference will be given as \Phi =tan^{-1}\frac{X_C-X_L}{R}=\frac{816.92-110.52}{500}=54.70

So current will be leading by an angle 54.70

5 0
3 years ago
Design a circuit with output f and inputs x1, x0, y1, and y0. Let X = x1x0 and Y = y1y0 represent two 2-digit binary numbers. Th
Viefleur [7K]

Complete question

The complete question is shown on the first uploaded image

Answer:

a The table is shown on the second uploaded image

b The simplest possible sum product is shown on the fifth uploaded image

Explanation:

The explanation is shown on the third fourth and fifth uploaded image

7 0
3 years ago
A rectangular conductor with a cross sectional area of 1.04 square millimeters (mm) ^2 has a resistance of 0.075 ohms. What woul
kogti [31]

Answer:

0.0375 ohms

Explanation:

The resistance of a material is the product of the resistivity of the material by the length of the material divided by its cross-section area.

Mathematically,

resistance= resistivity × length/area

In this case the resistivity of the material is the same, and the length is the same thus, assume a length of 1 unit, the cross-section area is the one changing

In applying the formula,

resistivity is r and length is l=1 unit, find the resistivity the material as;

resistance= resistivity * length /area

0.075=r*1/1.04

0.075=r*0.9615

0.075/0.9615 =r

r=0.078

use the r=0.078 , a length of 1 unit (assumed), and area of 2.08 mm² to find the new resistance

Resistance= resistivity * length /area

Resistance = 0.078*1/2.08

Resistance= 0.078 * 0.4807 = 0.0375 ohms

Point to note here is that the greater the cross-section area, the less the resistance.

4 0
3 years ago
Sea B = 5.00 m a 60.0°. Sea C que tiene la misma magnitud que A y un ángulo de dirección mayor que el de A en 25.0°. Sea A ⦁ B =
uranmaximum [27]

Answer:

\| \vec A \| = 6.163\,m

Explanation:

Sean A, B y C vectores coplanares tal que:

\vec A = (\| \vec A \|\cdot \cos \theta_{A},\| \vec A \|\cdot \sin \theta_{A}), \vec B = (\| \vec B \|\cdot \cos \theta_{B},\| \vec B \|\cdot \sin \theta_{B}) y \vec C = (\| \vec C \|\cdot \cos \theta_{C},\| \vec C \|\cdot \sin \theta_{C})

Donde \| \vec A \|, \| \vec B \| y \| \vec C \| son las normas o magnitudes respectivas de los vectores A, B y C, mientras que \theta_{A}, \theta_{B} y \theta_{C} son las direcciones respectivas de aquellos vectores, medidas en grados sexagesimales.

Por definición de producto escalar, se encuentra que:

\vec A \,\bullet\, \vec B = \|\vec A \| \| \vec B \| \cos \theta_{B}\cdot \cos \theta_{A} + \|\vec A \| \| \vec B \| \sin \theta_{B}\cdot \sin \theta_{A}

\vec B \,\bullet\, \vec C = \|\vec B \| \| \vec C \| \cos \theta_{B}\cdot \cos \theta_{C} + \|\vec B \| \| \vec C \| \sin \theta_{B}\cdot \sin \theta_{C}

Asimismo, se sabe que \| \vec B \| = 5\,m, \theta_{B} = 60^{\circ}, \vec A \,\bullet \,\vec B = 30\,m^{2}, \vec B\, \bullet\, \vec C = 35\,m^{2}, \|\vec A \| = \| \vec C \| y \theta_{C} = \theta_{A} + 25^{\circ}. Entonces, las ecuaciones quedan simplificadas como siguen:

30\,m^{2} = 5\|\vec A \| \cdot (\cos 60^{\circ}\cdot \cos \theta_{A} + \sin 60^{\circ}\cdot \sin \theta_{A})

35\,m^{2} = 5\|\vec A \| \cdot [\cos 60^{\circ}\cdot \cos (\theta_{A}+25^{\circ}) + \sin 60^{\circ}\cdot \sin (\theta_{A}+25^{\circ})]

Es decir,

30\,m^{2} = \| \vec A \| \cdot (2.5\cdot \cos \theta_{A} + 4.330\cdot \sin \theta_{A})

35\,m^{2} = \| \vec A \| \cdot [2.5\cdot \cos (\theta_{A}+25^{\circ})+4.330\cdot \sin (\theta_{A}+25^{\circ}})]

Luego, se aplica las siguientes identidades trigonométricas para sumas de ángulos:

\cos (\theta_{A}+25^{\circ}) = \cos \theta_{A}\cdot \cos 25^{\circ} - \sin \theta_{A}\cdot \sin 25^{\circ}

\sin (\theta_{A}+25^{\circ}) = \sin \theta_{A}\cdot \cos 25^{\circ} + \cos \theta_{A} \cdot \sin 25^{\circ}

Es decir,

\cos (\theta_{A}+25^{\circ}) = 0.906\cdot \cos \theta_{A} - 0.423 \cdot \sin \theta_{A}

\sin (\theta_{A}+25^{\circ}) = 0.906\cdot \sin \theta_{A} + 0.423 \cdot \cos \theta_{A}

Las nuevas expresiones son las siguientes:

30\,m^{2} = \| \vec A \| \cdot (2.5\cdot \cos \theta_{A} + 4.330\cdot \sin \theta_{A})

35\,m^{2} = \| \vec A \| \cdot [2.5\cdot (0.906\cdot \cos \theta_{A} - 0.423 \cdot \sin \theta_{A})+4.330\cdot (0.906\cdot \sin \theta_{A} + 0.423 \cdot \cos \theta_{A})]

Ahora se simplifican las expresiones, se elimina la norma de \vec A y se desarrolla y simplifica la ecuación resultante:

30\,m^{2} = \| \vec A \| \cdot (2.5\cdot \cos \theta_{A} + 4.330\cdot \sin \theta_{A})

35\,m^{2} = \| \vec A \| \cdot (4.097\cdot \cos \theta_{A} +2.865\cdot \sin \theta_{A})

\frac{30\,m^{2}}{2.5\cdot \cos \theta_{A}+ 4.330\cdot \sin \theta_{A}} = \frac{35\,m^{2}}{4.097\cdot \cos \theta_{A} + 2.865\cdot \sin \theta_{A}}

30\cdot (4.097\cdot \cos \theta_{A} + 2.865\cdot \sin \theta_{A}) = 35\cdot (2.5\cdot \cos \theta_{A}+4.330\cdot \sin \theta_{A})

122.91\cdot \cos \theta_{A} + 85.95\cdot \sin \theta_{A} = 87.5\cdot \cos \theta_{A} + 151.55\cdot \sin \theta_{A}

35.41\cdot \cos \theta_{A} = 65.6\cdot \sin \theta_{A}

\tan \theta_{A} = \frac{35.41}{65.6}

\tan \theta_{A} = 0.540

Ahora se determina el ángulo de \vec A:

\theta_{A} = \tan^{-1} \left(0.540\right)

La función tangente es positiva en el primer y tercer cuadrantes y tiene un periodicidad de 180 grados, entonces existen al menos dos soluciones del ángulo citado:

\theta_{A, 1} \approx 28.369^{\circ} y \theta_{A, 2} \approx 208.369^{\circ}

Ahora, la magnitud de \vec A es:

\| \vec A \| = \frac{35\,m^{2}}{4.097\cdot \cos 28.369^{\circ} + 2.865\cdot \sin 28.369^{\circ}}

\| \vec A \| = 6.163\,m

8 0
4 years ago
Which statement linking driving habits and fuel efficiency is true?
Dafna11 [192]

Answer: OC / THE 3 ANSWER

Explanation:

4 0
3 years ago
Other questions:
  • Technician A says diesel engines are also called compression ignition engines. Technician B says diesel engines have much higher
    9·1 answer
  • What colour is best for radiative heat transfer? a. Black b. Brown c. Blue d. White
    7·1 answer
  • Light energy produces the only voltage in a solar cell. (a)-True(T) (b)- false(F)
    9·1 answer
  • Engineering is the use of scientific principles to design and build machines, structures, and other items, including bridges, tu
    8·1 answer
  • a person who agrees to purchase the finished products or services presented with the prescribed or correct features​
    5·1 answer
  • Select the correct text in the passage.
    6·2 answers
  • 5√1024/4√1296+3√56/3√2401-4√16/3
    6·1 answer
  • There do u know it.............
    15·1 answer
  • Nitrogen (N2) enters an insulated compressor operating at steady state at 1 bar, 378C with a mass flow rate of 1000 kg/h and exi
    8·1 answer
  • Technician A says the cooling system must be full for a pressure test to be effective. Technician B says the cooling system shou
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!