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2 years ago

Que es el crecimiento?

Engineering

2 answers:

Vsevolod [243]2 years ago

7 0

Answer:

el crecimiento es una parte fundamental en la vida, ahí se desarrollan algunas partes del cuerpo y tu carácter es distinto al de tu niñez...

Explanation:

me das corona xfa ;-;

Grace [21]2 years ago

4 0

Answer:

El crecimiento es un concepto que se refiere al aumento de tamaño, cantidad o intensidad de algo. La palabra, como tal, deriva del verbo crecer, que a su vez proviene del verbo latino crescĕre. ... Sinónimos de crecimiento son aumento, incremento, ampliación, expansión. Antónimo de crecimiento es decrecimiento

Explanation:

You might be interested in

what is called periodic function give example? Plot the output which is started with zero degree for one coil rotating in the un

marta [7]

Answer:

A periodic function is a function that returns to its value over a certain period at regular intervals an example is the wave form of flux density (B) = sin wt

Explanation:

A periodic function is a function that returns to its value over a certain period at regular intervals an example is the wave form of flux density (B) = sin wt

attached to the answer is a free plot of the output starting with zero degree for one coil rotating in a uniform magnetic field

B ( wave flux density ) = Bm sinwt and w = 2 $\pi$ f = $\frac{2\pi }{T}$ rad/sec

3 0

2 years ago

Find the derivative of y = sin(ln(5x2 − 2x))

pickupchik [31]

Answer:

$y = \cos[\ln x + \ln (5\cdot x - 2)]\cdot \left(\frac{1}{x} + \frac{5}{5\cdot x-2} \right)$

Explanation:

Let $y = \sin[\ln(5\cdot x^{2}-2\cdot x)]$ and we proceed to find the derivative by the following steps:

1) $y = \sin[\ln(5\cdot x^{2}-2\cdot x)]$ Given

2) $y = \sin [\ln[x\cdot (5\cdot x - 2)]]$ Distributive property

3) $y = \sin[\ln x + \ln (5\cdot x - 2 )]$ $\ln (a\cdot b) = \ln a + \ln b$

4) $y = \cos[\ln x + \ln (5\cdot x - 2)]\cdot \left(\frac{1}{x} + \frac{5}{5\cdot x-2} \right)$ $\frac{d}{dx} (\sin x) = \cos x$ / $\frac{d}{dx}(\ln x) = \frac{1}{x}$ / $\frac{d}{dx}(c\cdot x^{n}) = n\cdot c\cdot x^{n-1}$ /Rule of chain/Result

3 0

3 years ago

5. A pump operating at steady state receives 1.2 kg/s of liquid water at 50o C, 1.5 MPa. The pressure of the water at the pump e

Andrew [12]

Answer:

the work required by a reversible pump operating with the same conditions, in kW is 16.39 kW

the isentropic pump efficiency is 78%

Explanation:

Given that;

m = 1.2 kg/sec

T = 50 degree Celsius { Vf = 0.001012 m^3/kg}

P1 = 1.5 Mpa

P2 = 15 Mpa

W-actual = 21 kw

W reversible = m*Vf (p2 - p1)

= 1.2 * 0.001012 * ( 15*10^3 - 1.5*10^3)

= 1.2 * 0.001012 * 13500

= 16.39 kW

the work required by a reversible pump operating with the same conditions, in kW is 16.39 kW

Isentropic Pump efficiency = W-reversible / W-actual

= 16.39 / 21 = 0.78

= 78%

the isentropic pump efficiency is 78%

6 0

3 years ago

What part connect to the tie rod that helps the brake chamber out that deals with slack adjuster

scoray [572]

Answer:

none

Explanation:

7 0

1 year ago

Determine the resistance values for a voltage divider that must meet the following specifications:_______.

Nikolay [14]

Answer:

i) when circuit is unloaded : R1 + R2 = 2kΩ.

ii) when 5V output voltage is applied : R1 = 1 kΩ , R2 = 1 kΩ

iii) when 2.5 v output voltage is applied : R1 = 1500 Ω, R2 = 500 Ω

iv) when: R1 = 1 kΩ , R2 = 1 kΩ is connected in parallel output voltage < 5 V

When : R1 = 1500 Ω, R2 = 500 Ω is connected in parallel output voltage > 2.5V

Explanation:

Current drawn from source under loaded condition ≤ 5 mA

source voltage = 10 v , required output = 5 v , 2.5 v

attached below is the sketch of the circuit

Resistance values

i) when the circuit is unloaded

Req = R1 + R2 = 2 kΩ ( Req = Vs / I = 10 / 5*10^-3 = 2 kΩ )

ii) when output voltage = 5 v

we will apply voltage divider rule

R1 = 1 kΩ ,

R2 = 1 kΩ

iii) When the output voltage = 2.5 v

applying voltage divider rule

R1 = 1500 Ω

R2 = 500 Ω

iv) when the load is connected to each tap one at a time

i.e. when the resistance are in parallel

when: R1 = 1 kΩ , R2 = 1 kΩ is connected in parallel output voltage < 5 V

When : R1 = 1500 Ω, R2 = 500 Ω is connected in parallel output voltage > 2.5V

attached below is the detailed solution to the given problem

8 0

3 years ago