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timofeeve [1]
3 years ago
7

what is called periodic function give example? Plot the output which is started with zero degree for one coil rotating in the un

iform magnetic field and name it. How can you represent this output as the periodic function?

Engineering
1 answer:
marta [7]3 years ago
3 0

Answer:

A periodic function is a function that returns to its value over a certain period at regular intervals an example is the wave form of flux density (B) = sin <em>wt</em>

Explanation:

A periodic function is a function that returns to its value over a certain period at regular intervals an example is the wave form of flux density (B) = sin <em>wt</em>

attached to the answer is a free plot of the output starting with zero degree for one coil rotating in a uniform magnetic field

B ( wave flux density ) = Bm sin<em>wt  and w = </em>2\pif = \frac{2\pi }{T} rad/sec

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The uniform beam is supported by two rods AB and CD that have crosssectional areas of 10 mm2 and 15 mm2 , respectively. Determin
ddd [48]

Answer:

w=2.25

Explanation:

It is necessary to determine the maximum w so that the normal stress in the AB and CD rods does not exceed the permitted normal stress.  

The surface of the cross-section of the stapes was determined:  

A_ab= 10 mm^2

A-cd=  15 mm^2

The maximum load is determined from the condition that the normal stresses is not higher than the permitted normal stress σ_allow.

σ_ab = F_ab/A_ab\leqσ_allow

σ_cd =  F_cd/A_cd\leqσ_allow

In the next step we will determine the static size: Picture b).  

We apply the conditions of equilibrium:  

∑F_x=0

∑F_y=0

  ∑M=0

∑M_a=0 ==> -w*6*0.5*6*0.75*F_cd*6 =0

              ==> F_cd = 2*w*k*N

∑F_y=0 ==> F_cd+F_ab - 6*w*0.5 ==>2*w+F_ab -6*w*0.5 =0

              ==> F_ab = w*k*N

Now we determine the load w  

<u>Sector AB:  </u>

σ_ab = F_ab/A_ab\leq σ_allow=300 KPa

         = w/10*10^-6\leq σ_allow=300 KPa

w_ab = 3*10^-3 kN/m

<u>Sector CD:  </u>

σ_cd = F_cd/A_cd\leq σ_allow=300 KPa

         = 2*w/15*10^-6\leq σ_allow=300 KPa

w_cd = 2.25*10^-3 kN/m

w=min{w_ab;w_cd} ==> w=min{3*10^-3;2.25*10^-3}

                                ==> w=2.25 * 10^-3 kN/m

<u>The solution is:  </u>

                                w=2.25 N/m

note:

find the attached graph

6 0
3 years ago
How nany degrées is the included angle of General Purpose Acme threads? A. 60 B. 29 c. 14.5 D. 10
horrorfan [7]

Answer:

B.29

Explanation:

In general purpose acme thread:

  Nominal depth of thread=0.5ltimes Pitch

  Included angle =29 degrees

Generally Acme thread are following types

  1.General purpose(G) Acme

  2.Centralizing(C) Acme

  3. Stub Acme  

Centralizing(C) Acme threads have tighter tolerance during manufacturing as compare to General purpose(G) Acme  threads.

8 0
3 years ago
An asphalt concrete mixture includes 94% aggregates by weight. The specific gravity of aggregate and asphalt are 2.7 and 1.0, re
riadik2000 [5.3K]

Answer:

The correct solution is "5.74%".

Explanation:

The given values are:

Gravity of aggregate,

G_{agg}=2.7

Gravity of asphalt,

G_{asp}=1.0

Asphalt concrete mixture,

W_{agg}=0.94 \ W_m

We know that,

W_{asp}=W_m-W_{agg}

        =0.06 \ W_m

Now,

The theoretical specific gravity of mix,

⇒ G_t=\frac{W_{agg}+W_{asp}}{\frac{W_{agg}}{G_{agg}} +\frac{W_{asp}}{G_{asp}} }

By putting the values, we get

         =\frac{0.94 \ Wm+0.06 \ Wm}{\frac{0.94 \ Wm}{2.7} +\frac{0.06 \ Wm}{1} }

         =2.45

hence,

The percentage of voids will be:

⇒  %V = \frac{G_t-G_m}{G_t}\times 100

           = \frac{2.45-2.317}{2.45}\times 100

           = \frac{0.133}{2.317}\times 100

           = 5.74 (%)  

8 0
3 years ago
Think about all the things that you have learned about wildfire in this module.
astra-53 [7]

Answer:

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Explanation:

6 0
3 years ago
Does anybody want 20 points? They're free get 'em while ya can...
DedPeter [7]

Answer:

hi

Explanation:

4 0
3 years ago
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