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Dmitrij [34]
3 years ago
9

Find the derivative of y = sin(ln(5x2 − 2x))

Engineering
1 answer:
pickupchik [31]3 years ago
3 0

Answer:

y = \cos[\ln x + \ln (5\cdot x - 2)]\cdot \left(\frac{1}{x} + \frac{5}{5\cdot x-2} \right)

Explanation:

Let y = \sin[\ln(5\cdot x^{2}-2\cdot x)] and we proceed to find the derivative by the following steps:

1) y = \sin[\ln(5\cdot x^{2}-2\cdot x)] Given

2) y = \sin [\ln[x\cdot (5\cdot x - 2)]] Distributive property

3) y = \sin[\ln x + \ln (5\cdot x - 2 )] \ln (a\cdot b) = \ln a + \ln b

4) y = \cos[\ln x + \ln (5\cdot x - 2)]\cdot \left(\frac{1}{x} + \frac{5}{5\cdot x-2} \right)  \frac{d}{dx} (\sin x) = \cos x/\frac{d}{dx}(\ln x) = \frac{1}{x}/\frac{d}{dx}(c\cdot x^{n}) = n\cdot c\cdot x^{n-1}/Rule of chain/Result

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The strength and stiffness of a properly constructed composite buildup depends primarily on?
Flauer [41]

Answer:orientation of piles

Explanation:

The stiffness and strength of a properly constructed composite buildup depend upon the orientation of piles to the load direction.

Structural composite materials are designed and manufactured to withstand certain specific stress loads. The ability to withstand these stress loads depends, to a large extent, on how the fibers are arranged. The fiber orientation of the parts must be the same as that of the original form.          

4 0
3 years ago
State and explain briefly four (4) functions that a machine foundation should fulfill.
MrMuchimi

Answer:

1 The weight of the foundation block should be enough to withstand vibrations

2 The foundation must be so dimensional that the resulting pressure due to weight of the device as well as the weight of foundation moves through the center of gravity of a base impact area in order to avoid the risk of specific settlement.

3.The base should be sufficiently rigid to have the requisite rigidity

4 a distance should be created all across  machine foundation to separate it from the adjacent parts of the building

Explanation:

 1. The weight of the foundation block should be enough to withstand vibrations and to avoid friction between device and the surrounding soil as well. This can be done by increasing the base block weight in supporting with engine power

2.The foundation must be so dimensional that the resulting pressure due to weight of the device as well as the weight of foundation moves through the center of gravity of a base impact area in order to avoid the risk of specific settlement.

3.The base should be sufficiently rigid to have the requisite rigidity as the slightest misdirection of foundation may cause significant bearing disorders.

4.To avoid propagation of vibration from a device to the adjacent parts of the building, a distance should be created all across  machine foundation to separate it from the adjacent parts of the building. 

8 0
4 years ago
Suppose that you are working in a home that has a 15kw oven that operates on 240 V, The oven is on a branch circuit by itself. W
krok68 [10]

Explanation:

please see it my work solution

7 0
3 years ago
Determine the specific volume of superheated water vapor at 15 MPa and 350°C, using a. The ideal-gas equation Answer: 0.01917 m3
ollegr [7]

Answer:

specific volume by ideal gas equation = 0.01917 m³/kg

specific volume by compressibility chart = 0.01246 m³/kg

specif volume by super heated stream table is 0.0114810 m³/kg

Explanation:

given data

temperature  T = 350°C = 623 K

pressure P = 15 MPa = 15000 kPa

to find out

specific volume by  ideal-gas equation ,generalized compressibility chart and steam tables

solution

we will apply here ideal gas equation that is

specific volume = \frac{R*T}{P}   ..............1

here P is pressure and T is temperature and R is gas constant i.e 0.4615 kJ/kg-K

specific volume =  \frac{0.4615*623}{15000}

specific volume = 0.01917 m³/kg

and

by the compressibility chart

critical pressure of water Pcr = 22.06 Mpa

and critical temperature of water Tcr = 647.1 K

so

reduced pressure will be = \frac{P}{Pcr}

reduced pressure = \frac{15}{22.06} = 0.68 Mpa

and

reduced temperature will be = \frac{T}{Tcr}

reduced pressure = \frac{623}{647.1} = 0.963 K

so by compressibility chart pressure 0.68 Mpa and temperature 0.963 K

compressibility factor Z is 0.65

so

specific volume = compressibility factor Z × ideal specific volume

specific volume = 0.65 × 0.01917

specific volume = 0.01246 m³/kg

and

by the steam table

use here super heated stream table for

pressure = 15 Mpa

ans temperature = 350°C

so

specif volume by super heated stream table is 0.0114810 m³/kg

6 0
4 years ago
For a bolted assembly with six bolts, the stiffness of each bolt is kb=Mlbf/in and the stiffness of the members is km=12Mlbf/in.
makkiz [27]

Answer:

  • nP  ≈ 4.9
  • nL =  1.50

Explanation:

GIVEN DATA

external load applied (p) = 85 kips

bolt stiffness ( Kb ) = 3(10^6) Ibf / in

Member stiffness (Km) = 12(10^6) Ibf / in

Diameter of bolts ( d ) = 1/2 in - 13 UNC grade 8

Number of bolts = 6

assumptions

for unified screw threads UNC and UNF

tensile stress area ( A ) = 0.1419 in^2

SAE specifications for steel bolts for grade 8

we have

Minimum proff strength ( Sp) = 120 kpsi

Minimum tensile strength (St) = 150 Kpsi

Load Bolt (p) = external load / number of bolts = 85 / 6 = 14.17 kips

Given the following values

Fi = 75%* Sp*At = (0.75*120*0.1419 ) = 12.771 kip

Preload stress

αi = 0.75Sp = 0.75 * 120 = 90 kpsi

stiffness constant

C = \frac{Kb}{Kb + Km}  = \frac{3}{3+2} = 0.2

A) yielding factor of safety

nP = \frac{sPAt}{Cp + Fi} = \frac{120* 0.1419}{0.2*14.17 + 12.771}

nP = 77.028 / 15.605 = 4.94 ≈ 4.9

B) Determine the overload factor safety

nL = \frac{SpAt - Fi}{CP} = ( 120 * 0.1419) - 12.771 / 0.2 * 14.17

= 17.028 - 12.771 / 2.834

= 1.50

3 0
3 years ago
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