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sveticcg [70]
3 years ago
12

Calculate the mass in grams of each of the followinga. 5.94 x 10^20 H2O2 moleculesb. 2.8 x 10^22 SO2 moleculesc. 4.5 x 10^25 O3

moleculesd. 9.85 x 10^19 CH4 molecules
Chemistry
1 answer:
ryzh [129]3 years ago
4 0

Answer:

0.0335\ \text{g}

2.978\ \text{g}

3586.84\ \text{g}

0.0026\ \text{g}

Explanation:

Mass in grams is given by

m=\dfrac{nM}{N_A}

where

n = Number of molecules

N_A = Avogadro's number = 6.022\times 10^{23}\ \text{mol}^{-1}

M = Molar mass of molecule

Molar mass of H_2O_2 = 34.0147 g/mol

n=5.94\times 10^{20}

m=\dfrac{5.94\times 10^{20}\times 34.0147}{6.022\times 10^{23}}\\\Rightarrow m=0.0335\ \text{g}

Mass of H_2O_2=0.0335\ \text{g}

Molar mass of SO_2 = 64.066 g/mol

n=2.8\times 10^{22}

m=\dfrac{2.8\times 10^{22}\times 64.066}{6.022\times 10^{23}}\\\Rightarrow m=2.978\ \text{g}

Mass of SO_2=2.978\ \text{g}

Molar mass of O_3 = 48 g/mol

n=4.5\times 10^{25}

m=\dfrac{4.5\times 10^{25}\times 48}{6.022\times 10^{23}}\\\Rightarrow m=3586.84\ \text{g}

Mass of O_3=3586.84\ \text{g}

Molar mass of CH_4 = 16.04 g/mol

n= 9.85\times 10^{19}

m=\dfrac{9.85\times 10^{19}\times 16.04}{6.022\times 10^{23}}\\\Rightarrow m=0.0026\ \text{g}

Mass of CH_4=0.0026\ \text{g}

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Answer:

The answer is "= 0.078 \ kg \ H_2".

Explanation:

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Eqution:

CH_4 +H_2O \to  3H_2+ CO \ (g)

Calculating the amount of H_2 produced:

= 12.9 \ mol CH_4 \times  \frac{3 \ mol \ H_2 }{1 \ mol \ CH_4}\times \frac{2.016 g H_2}{1 \ mol \ H_2}\\\\= 78 \ g \ H_2 \\\\= 0.078 \ kg \ H_2

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3 years ago
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You have 100 mL of a 12M solution of HCl, and you need to dilute it to 1.5M for an experiment. How many liters will your new sol
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Answer:

800.0 mL.

Explanation:

  • To solve this problem; we must mention the rule states the no. of millimoles of a substance before and after dilution is the same.

<em>(MV)before dilution of HCl = (MV)after dilution of HCl</em>

M before dilution = 12.0 M, V before dilution = 100.0 mL.

M after dilution = 1.5 M, V after dilution = ??? mL.

∵ (MV)before dilution of HCl = (MV)after dilution of HCl

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Hydrazine (N2H4) is used as rocket fuel. It reacts with oxygen to form nitrogen and water.
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Answer:

See explanation below for answers

Explanation:

This is a stochiometry reaction. LEt's write the overall reaction again:

N₂H₄ + O₂ ---------> N₂ + 2H₂O

This reaction is taking place at Standard temperature and pressure conditions (STP) which are P = 1 atm and T = 273 K.  To know the volume of N₂ formed, we need to know first how many moles are formed, and this can be calculated with the reagents and the limiting reagent. Let's calculate the moles first of the reagents:

MM N₂H₄ = 32 g/mol;    MM O₂ = 32 g/mol

mol N₂H₄ = 2000 / 32 = 62.5 moles

mol O₂ ? 2100 / 32 = 65.63 moles

Now that we have the moles, we need to apply the stochiometry and calculate the limiting reagent. According to the overall reaction we have a mole ratio of 1:1 between N₂H₄ and O₂, therefore:

1 mole N₂H₄ ---------> 1 mole O₂

62.5 moles ----------> X

X = 62.5 moles of O₂

But we have 65.63 moles, therefore, the limiting reactant is the N₂H₄.

We also have a 1:1 mole ratio with the N₂, so:

moles N₂H₄ = moles N₂ = 62.5 moles

Now that we have the moles, we can calculate the volume with the ideal gas equation:

PV = nRT

V = nRT / P

R: gas constant (0.082 L atm / K mol)

Replacing we have:

v = 62.5 * 0.082 * 273 / 1

V = 1399.13 L of N₂

Now, how many grams of the excess remains?, we know how many moles are reacting so, let's see how much is left:

moles remaining = 65.63 - 62.5 = 3.12 moles

then the mass of oxygen:

m = 3.12 * 32 = 100.16 g of O₂

7 0
3 years ago
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What is the mass of 1 mole of lithium?
Korolek [52]

<u>Answer:</u> The mass of 1 mole of lithium is 6.941 grams.

<u>Explanation:</u>

To calculate the mass of a compound or element, we use the formula used to calculate the number of moles:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Where,

Number of moles of lithium = 1 mole

Given mass of lithium = ? g

Molar mass of lithium = 6.941 g/mol

Putting value in above equation, we get:

1mole=\frac{\text{Given mass}}{6.941g/mol}\\\\\text{Mass of lithium}=6.941g

Hence, the mass of 1 mole of lithium is 6.941 grams.

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3 years ago
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