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4 years ago

What changes if the degree (amount) of intermolecular bonds of a substance are changed?

Chemistry

2 answers:

elixir [45]4 years ago

7 0

<h2>Answer:</h2>

The correct answers are;

volume of a substance

density of a substance

The volume and the density of the substance depend on inter molecular forces of the substance. So, when we will change the degree of inter molecular forces, whether decrease it or increase it, it will affect the volume and density of a substance.

Nuetrik [128]4 years ago

6 0

Answer: The correct statements are volume of a substance and density of a substance.

Explanation:

Degree of intermolecular bonds is defined as the forces by which two particles are bonded in a substance. If the intermolecular forces are strong, it means that it will occupy less space or volume and hence, the density of that substance will be more.

If the intermolecular forces are weak, it means that it will occupy less space and density of the substance will be more.

Relationship between volume and density of a substance is given by the relation:

$Density=\frac{Mass}{Volume}$

Density and volume has inverse relationship. If volume increases, density will decrease and vice-versa.

Hence, the correct statements are volume of a substance and density of a substance.

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6. What is the molarity of 175 mL of solution containing 2.18 grams of NazS04-10H2O?

Ymorist [56]

Answer:

$Molarity\,\,of\,\,the\,\,solution\,\,is\,\,S=0.039M$

Explanation:

$W=2.18 g\\M=322g\\V=175mL=0.175L\\\\S=\frac{W}{MV} \\=>S=\frac{2.18}{322*0.175} \\So,S=0.039M$

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8 0

3 years ago

When two intermediate chemical equations are combined, the same substance that appears in the same phase can be canceled out, pr

xxTIMURxx [149]

Answer: Option (C) is the correct option.

Explanation:

When two intermediate chemical equations are combined, the same substance that appears in the same phase can be canceled out, provided that it is a reactant in one intermediate reaction and a product in the other reaction.

For example,

$2Al(s) + 2KOH(aq) + 6H_{2}O\rightarrow 2KAl(OH)_{4}(aq)+ 3H_{2}(g)$ ....(1)

$2KAl(OH)_{4}(aq) + 4H_{2}SO_{4}(aq) + 6H_{2}O(l)\rightarrow 2KAl(SO_{4})_{2}(aq)+ 12H_{2}O(s)$ .........(2)

Cancelling the common species in both the equations as follows.

$2Al(s) + 2KOH(aq) + 6H_{2}O\rightarrow \not{2KAl(OH)_{4}(aq)}+ 3H_{2}(g)$

$\not{2KAl(OH)_{4}(aq)}+ 4H_{2}SO_{4}(aq) + 6H_{2}O(l)\rightarrow 2KAl(SO_{4})_{2}(aq)+ 12H_{2}O(s)$

Therefore, on addition we get the equation as follows.

$2Al(s)+ 2KOH(aq) + 4H_{2}SO_{4}(aq) + 22H_{2}O(l)\rightarrow 3H_{2}(g)+ 2KAl(SO_{4})_{2} + 12H_{2}O(s)$

3 0

4 years ago

Read 2 more answers

The isotope of an atom containing 31 protons and 39 neutrons suddenly has 2 neutrons added to it. What isotope is created?

Hunter-Best [27]

Answer,

A. Gallium-72

Hope this helps :-)

6 0

4 years ago

7.5 g of aluminum reacts with an excess of oxygen how many grams of aluminum oxide are produced?

ycow [4]

14.2 grams
Let's start by looking up the atomic weights of aluminum and oxygen. Atomic weight aluminum = 26.981539
Atomic weight oxygen = 15.999
Moles Al = 7.5 g / 26.981539 g/mol = 0.277967836
The formula for aluminum oxide is Al2O3, so for every 2 moles of Al, 3 moles of O is required. So let's calculate the number of moles of O we need and from that the mass.
0.277967836 mol / 2 * 3 = 0.416951754 mol
Mass O2 = 0.416951754 * 15.999 = 6.670811105
The mass of aluminum oxide is simply the mass of aluminum plus the mass of oxygen. So:
7.5 g + 6.670811105 g = 14.17081111 g
Rounding to 1 decimal place gives 14.2 g.

3 0

3 years ago

How are a dog, a dolphin, and a bat similar to a human?

pentagon [3]

Answer:

The more structures that are similar, the more closely related organisms are in their evolutionary past. For example, a human, a dog, a fruit bat, and a dolphin all have the same pattern of bone structure in the upper extremity—one bone connected to two bones, connected to many bones, connected to finger-like bones.

8 0

3 years ago

Read 2 more answers