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3 years ago

What changes if the degree (amount) of intermolecular bonds of a substance are changed?

Chemistry

2 answers:

elixir [45]3 years ago

7 0

<h2>Answer:</h2>

The correct answers are;

volume of a substance

density of a substance

The volume and the density of the substance depend on inter molecular forces of the substance. So, when we will change the degree of inter molecular forces, whether decrease it or increase it, it will affect the volume and density of a substance.

Nuetrik [128]3 years ago

6 0

<u>Answer:</u> The correct statements are volume of a substance and density of a substance.

<u>Explanation:</u>

Degree of intermolecular bonds is defined as the forces by which two particles are bonded in a substance. If the intermolecular forces are strong, it means that it will occupy less space or volume and hence, the density of that substance will be more.

If the intermolecular forces are weak, it means that it will occupy less space and density of the substance will be more.

Relationship between volume and density of a substance is given by the relation:

$Density=\frac{Mass}{Volume}$

Density and volume has inverse relationship. If volume increases, density will decrease and vice-versa.

Hence, the correct statements are volume of a substance and density of a substance.

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Answer:

$\boxed{\text{8 da}}$

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$\begin{array}{cccl}\textbf{No. of} & & \textbf{Fraction} & \\\textbf{half-lives} & \textbf{t/da} & \textbf{remaining} & \\1 & 4 & \dfrac{1}{2} & \\\\2 & 8 & \dfrac{1}{4}& \\\\3 & 12 & \dfrac{1}{8}& \\\end{array}$

$\text{We see that 8 da is two half-lives, and the fraction of the element remaining is $\frac{1}{4}$.}\\\text{It takes $\boxed{\textbf{8 da}}$ for three-fourths of the element to decay}$

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