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3 years ago

A sample of gas has a volume of 3.00 liters at a temperature of 30.℃. At what temperature would the volume be 1.50 liters?

Chemistry

1 answer:

erastovalidia [21]3 years ago

3 0

The answer I got is 151. 5 K. I hope that helps.

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Calculate the mass of water produced by metabolism 84.0 g of glucose

scoundrel [369]

The amount of water that will be produced is 50.36 grams

<h3>Stoichiometric problems</h3>

The metabolism of glucose is represented by the following equation:

$C_6H_1_2O_6(s)+6O_2(g)--- > 6CO_2(g)+6H_2O(g)$

The mole ratio of glucose metabolized to the water produced is 1:6.

Mole of 84.0 g glucose = 84/180.156 = 0.4662 moles

Equivalent mole of water = 0.4662 x 6 = 2.7975 moles

Mass of 2.7975 moles water = 2.7975 x 18 = 50.36 grams

More on stoichiometric problems can be found here: brainly.com/question/14465605

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8 0

2 years ago

What can physical properties not separate?

Mashutka [201]

Color, phase, odor and boiling point are the physical properties. Reactivity with oxygen depends on the chemical nature of object, thus, it is not a physical property. It is a chemical property.

6 0

3 years ago

A block of iron has a mass of 826 g. What is the volume of the block of iron whose density at 25°C is 7.9

LuckyWell [14K]

Answer:

105

Explanation:

Density = mass/volume

therefore volume = mass/density

826/7.9=105 (To three significant figure)

8 0

3 years ago

Which formula can be used to calculate the theoretical yield? (5 points)

Semenov [28]

Answer:

Multiply the number of moles in the product by the molecular weight of the product to determine the theoretical yield.

Explanation:

For example:

If you created 0.5 moles of Aluminium Oxide the molecular weight of Aluminium Oxide is 101.96g/mole, so you would get 50.98g as the theoretical yield.

So multiply,..

101.96x0.5= 50.98

This is the correct way to calculate the theoretical yield

......

8 0

4 years ago

This question has multiple parts. Work all the parts to get the most points. An aqueous antifreeze solution is 39.0% ethylene gl

nlexa [21]

Answer:

Molality = 10.300 m

Molarity = 6.5970 M

mole fraction = 0.156549

Explanation:

39.0 % = ethylene glycol

61.0 % = water

imagine the total mass = 100g

39.0% ethylene glycol = 39g

61.0 % water = 61g

1) Molality = number of moles / mass of solvent (kg)

Molar mass of ethylene glycol = 62.07g/mole

mole = 39g / 62.07g/mole = 0.6283 moles

Molality = moles / mass of solvent = 0.6283 moles / 0.061kg = 10.300 m

2) Molarity = number of moles / volume of solution

Since we know the density of the solution = 1.05g /ml

⇒ volume = 100g / 1.05g /mL = 95.24 mL = 0.09524 L

Molarity = 0.6283 moles / 0.09524 L = 6.5970 M

3) Mole fraction

moles water = 61g / 18.02g/mole = 3.38513 moles

Total number of moles = moles of ethylene glycol + moles of water = 0.6283 + 3.38513 = 4.0134276 moles

Mole fraction = 0.6283/ 4.0134276 = 0.156549

3 0

3 years ago