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kolbaska11 [484]
3 years ago
7

Water has a heat capacity of 4.184J/g C. If 50 g of water has a temperature of 30°C and as added to the water causing the

Chemistry
1 answer:
Irina-Kira [14]3 years ago
3 0
Answer is 3 so correct answer is 3
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what is the correct electron configuration for an element with five electrons in the third energy level
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That would be phosphorus. It’s electron configuration is 1s^2 2s^2 2p^6 3s^2 3p^3
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What is the theory that can explain the model of Pangaea?
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The bones of the same animal found out continents far away from each other
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A ___ such as h20 is a symbol that shows the elements in a compound and the ratio of atoms
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3 years ago
An electrochemical cell has the following standard cell notation.
icang [17]

The cell notation is:

Mg(s)|Mg^{+2}(aq)||Ag^{+}(aq)|Ag(s)

here in cell notation the left side represent the anodic half cell where right side represents the cathodic half cell

in anodic half cell : oxidation takes place [loss of electrons]

in cathodic half cell: reduction takes place [gain of electrons]

1) this is a galvanic cell

2) the standard potential of cell will be obtained by subtracting the standard reduction potential of anode from cathode

E^{0}_{Mg}=-2.38V

E^{0}_{Ag}=+0.80V

Therefore

E^{0}_{cell}=0.80-(-2.38)=+3.18V

3) as the value of emf is positive the reaction will be spontaneous as the free energy change of reaction will be negative

ΔG^{0}=-nFE^{0}

As reaction is spontaneous and there will be conversion of chemical energy to electrical energy it is a galvanic cell.

7 0
3 years ago
A soft silvery metal has two naturally occurring isotopes: mass 84.9118, accounting for 72.15% and mass 86.9092, accounting for
zloy xaker [14]

Answer: The atomic weight of the metal would be 85.47.

Explanation:

Mass of isotope 1 of metal = 84.9118

% abundance of isotope 1 of metal = 72.15% = \frac{72.15}{100}

Mass of isotope 2 of metal= 86.9092

% abundance of isotope 2 of metal = 27.85% = \frac{27.85}{100}

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(84.9118)\times \frac{72.15}{100})+(86.9092)\times \frac{27.85}{100}]]

A=85.47

Therefore, the atomic weight of the metal would be 85.47.

6 0
3 years ago
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