Answer:
88%.
Explanation:
The percentage yield of lead sulfate in this experiment is 88% if 2.53 is divided by 2.85 and multiply by 100. The percentage yield can be calculated when the experimental yield is divided by theoretical yield and then multiply by 100. The percentage yield tells us about the actual yield that is gained in the end of experiment which is lower than theoretical yield.
The given blank can be filled with endothermic reactions.
The endothermic reactions or processes captivates energy from its surroundings, primarily, but will not always be in the form of heat. A reaction, which requires the input of energy that dissociates a bond will always be endothermic. The best examples of endothermic reactions are evaporation of the liquid, melting cubes, melting or solid salts, and others.
Answer:
62.3 moles of Ca
Explanation:
1 mole of a substance is defined as 6.022x10²³ particles of this substance. For example:
1mol of electrons = 6.022x10²³electrons
1mol of atoms = 6.022x10²³atoms
1 mol of molecules = 6.022x10²³ molecules
And 1mol of atoms of Ca = 6.022x10²³ atoms of Ca
That means 3.75x10²⁵ atoms of Ca are:
3.75x10²⁵ atoms of Ca * (1 mole of Ca / 6.022x10²³ atoms) =
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62.3 moles of Ca
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Combustion of hydrocarbons is when C and H containing compounds are burnt in O₂
the balanced chemical reaction for combustion of C₄H₁₀ (butane) is as follows;
2C₄H₁₀ + 13O₂ ---> 8CO₂ + 10H₂O
the stoichiometry of C₄H₁₀ to CO₂ is 2;4, simplified ratio is 1:2
this means that for every 1 mole of butane used up,4 moles of CO₂ are formed
molar mass of butane - (12 g/mol *4) + (1 g/mol * 10) = 58 g/mol
58 g of butane - 1 mol
Therefore 4.37 g of butane - 1/58 g/mol * 4.37g = 0.075 mol
1 mol of butane forms --> 4 mol of CO₂
Therefore 0.075 mol of butane forms = 4 x 0.075 mol = 0.3 mol of CO₂
molar mass of CO₂ = 44 g/mol
mass of CO₂ formed = 0.3 mol * 44 g/mol = 13.2 g of CO₂ is formed
Hi! The answer is "A. Anopheles", malaria is a mosquito-borne parasitic spread by anopheles mosquitoes.