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dimaraw [331]
3 years ago
13

If the same amount of energy in the form of heat is added to 8.9 g samples of each of the metals below, which metal will undergo

the largest temperature change?
Chemistry
1 answer:
elena-14-01-66 [18.8K]3 years ago
8 0

Answer:

Explanation:

The metal with the highest specific heat capacity will undergo the most temperature change.

Specific heat capacity is the amount of heat supplied to a unit mass of a substance to cause a temperature change of 1°C.

A very good conductor of heat will have low specific heat capacity. This implies that less heat will be required to cause a monumental change in its temperature.

                  C  = \frac{H}{m (t2  - t1)}

where C  is specific heat

            H is the amount of heat supplied

            m is the mass

             t is the temperature

We see that since both H and m for the two metals are the same, specific heat is inversely proportional to temperature change.

The lower the heat capacity, the higher the temperature change.

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What is the volume of an object with a density of 2.6 g/cm³ and a mass of 30.5g?
inessss [21]

Answer:

The answer is

<h2>11.73 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}

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mass of object = 30.5 g

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We have the final answer as

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Hope this helps you

5 0
3 years ago
I need help solving this!
zmey [24]

Answer: Moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, CH_{4}.

Explanation:

Given: Mass of methane = 146.6 g

As moles is the mass of a substance divided by its molar mass. So, moles of methane (molar mass = 16.04 g/mol) are calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{146.6 g}{16.04 g/mol}\\= 9.14 mol

The given reaction equation is as follows.

C + 2H_{2} \rightarrow CH_{4}

This shows that 2 moles of hydrogen gives 1 mole of methane. Hence, moles of hydrogen required to form 9.14 moles of methane is as follows.

Moles of H_{2} = \frac{9.14}{2}\\= 4.57 mol

Thus, we can conclude that moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, CH_{4}.

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