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Kay [80]
2 years ago
15

A 64-kg skater initially at rest throws a 4.0-kg medicine ball horizontally to the left. Suppose the ball is accelerated through

a distance of 1.0 mm before leaving the skater's hand at a speed of 7.0 m/s. Assume the skater and the ball to be point-like and the surface to be frictionless and ignore air resistance. Use a vertical y-axis with the positive direction pointing up and a horizontal x-axis with the positive direction pointing to the right.
Required:
a. Determine the acceleration of the ball during the throw.
b. Determine the acceleration of the skater during the throw.
Physics
2 answers:
maxonik [38]2 years ago
7 0

Explanation:

64-kg skater initially at rest throws a 4.0-kg medicine ball horizontally to the left. Suppose the ball is accelerated through a distance of 1.0 mm before leaving the skater's hand at a speed of 7.0 m/s. Assume the skater and the ball to be point-like and the surface to be frictionless and ignore air resistance. Use a vertical y-axis with the positive direction pointing up and a horizontal x-axis with the positive direction pointing to the right.

Required:

a. Determine the acceleration of the ball during the throw.

b. Determine the acceleration of the skater during the throw.

vlabodo [156]2 years ago
6 0

Answer:

yeah

Explanation:

Solved: Problem 2.41 A 64-kg Skater Initially At Rest Thro ...www.chegg.com › ... › physics questions and answers

Suppose The Ball Is Accelerated Through A Distance Of 1.0 M Before Leaving The Skater's Hand At A Speed Of 7.0 M/s . Assume The Skater And The Ball To Be Point-like, The Surface To Be Frictionless, And Ignore Air Resistance. Use A ... A 64-kg skater initially at rest throws a 5.0-kg medicine ball horizontally to the left

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Suppose a 4.0-kg projectile is launched vertically with a speed of 8.0 m/s. What is the maximum height the projectile reaches?
eduard

Answer:

h = 3.3 m (Look at the explanation below, please)

Explanation:

This question has to do with kinetic and potential energy. At the beginning (time of launch), there is no potential energy- we assume it starts from the ground. There, is, however, kinetic energy

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