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vovikov84 [41]
3 years ago
6

A spring with spring constant 200N/m is compressed by 4cm by applying a force. What is the applied force

Physics
1 answer:
Dafna11 [192]3 years ago
8 0

Answer:

396 needa bigger clue like a graph

Explanation:

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Determine the frequency of the 2nd harmonic of a spring that has a 3rd harmonic resonance of f3=512 Hz.
Elena L [17]

Answer:

1) 341 Hz

Explanation:

When a string vibrates, it can vibrate with different frequencies, corresponding to different modes of oscillations.

The fundamental frequency is the lowest possible frequency at which the string can vibrate: this occurs when the string oscillate in one segment only.

If the string oscillates in n segments, we say that it is the n-th mode of vibration, or n-th harmonic.

The frequency of the n-th harmonic is given by

f_n = nf_1

where

n is the number of the harmonic

f_1 is the fundamental frequency

Here we have:

f_3=512 Hz is the frequency of the 3rd harmonic

So the fundamental frequency is

f_1=\frac{f_3}{3}=\frac{512}{3}=170.7 Hz

And so, the frequency of the 2nd harmonic is:

f_2=2f_1=2(170.7)=341.3 Hz

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4 years ago
A _________________ is when the courts allow people who have all been harmed to pool grievances and sue for damages on behalf of
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A class action law suit is one in which the courts allow several
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and sue for damages on behalf of the group.

4 0
4 years ago
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1. Which of the following identifies the part of blood shown in B and describes its function? (1 point)
Lelechka [254]
White blood cells fight boy invaders to the body.
6 0
3 years ago
HELP ASAP CORRECT ANSWER ONLY 10 PTS Collaboration, listening, and negotiating are considered __________ skills. interpersonal m
Jet001 [13]

Answer:

Explanation:

verbal as they are all linked to communication and speaking

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4 years ago
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A certain kind of glass has an index of refraction of 1.660 for blue light of wavelength 420 nm and an index of 1.630 for red li
Bogdan [553]

Answer:

Explanation:

Using Snell's law

n₁ sinθ₁ = n₂ sinθ₂

for 420 nm wavelength

where n₁ = 1.00 ( refractive index of air) and θ₁ = 30° n₂ = 1.660

1.00 × sin 30° = 1.660 sinθ₂

sinθ₂ = 0.3012

θ₂ = sin⁻¹ 0.3012 = 17.53°

for 690 nm wavelength

n₁ sinθ₁ = n₂ sinθ₂

sinθ₂ = 0.5 / 1.630

θ₂ = sin⁻¹ 0.3067 = 17.86°

the angle between the two beam = 17.863° - 17.53° = 0.333°

7 0
3 years ago
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