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Korolek [52]
4 years ago
14

The temperature of two bodies differ by 1°c. how much will they differ in Fahrenheit?​

Physics
2 answers:
Tamiku [17]4 years ago
7 0

Answer:

the answer is 1.8°f...

Verizon [17]4 years ago
7 0

Answer:

33.8 degrees.

Explanation:

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The atomic number of an element is found by?
azamat

Calculate the number of neutrons. Now you know that atomic number = number of protons, and mass number = number of protons + number of neutrons. To find the number of neutrons in an element, subtract the atomic number from the mass number.

6 0
3 years ago
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A baseball rolls along a flat parking lot in a straight line at a constant speed of 3.8 m/s. How
Studentka2010 [4]

This is a uniform rectilinear motion (MRU) exercise.

To start solving this exercise, we obtain the following data:

<h3><u>DATA:</u></h3>
  • V = 3.8 m/s
  • D = ¿?
  • T = 15 sec

To calculate the distance, multiply the speed by the time.

We apply the following formula: d = v * t

We clear our data in the formula:

\bf{d=3.8\dfrac{m}{\not{s}}*15 \not{s} }

\bf{d=57 \ m}

The baseball in 15 seconds will roll a distance of 57 meters.

<h2>{ Pisces04 }</h2>
3 0
2 years ago
After 24.0 days 2.00 milligrams of an original 128.0. Milligram sample remain what is the half life of the sample
alina1380 [7]

Answer:

4 days

either multiply 128 by .5 until you get to 2 counting each time or use 2 formulas ln(n2/n1)=-k(t2-t1) to get k then input k into ln(2)=k*t1/2

n2 is final amount and n1 is beginning and t is either time elapsed as in the first formula or the actual half life that is t1/2

Explanation:

5 0
4 years ago
An automobile traveling 92.0 km/h has tires of 64.0 cm diameter. (a) What is the angular speed of the tires about their axles? (
Semenov [28]

Answer:

76.4035 m

Explanation:

r = Radius = 0.32 m

\omega_f = Final angular velocity = 0

\omega_i = Initial angular velocity = 92 km/h

\alpha = Angular acceleration

\theta = Angle of rotation

Angular speed is given by

\omega=\dfrac{v}{r}\\\Rightarrow \omega=\dfrac{\dfrac{92}{3.6}}{0.32}\\\Rightarrow \omega=79.861\ rad/s

The angular speed of the tires about their axles is 79.861 rad/s.

\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \alpha=\frac{\omega_f^2-\omega_i^2}{2\theta}\\\Rightarrow \alpha=\frac{0^2-79.861^2}{2\times 2\pi \times 38}\\\Rightarrow \alpha=-13.355\ rad/s^2

The magnitude of acceleration is 13.355 m/s²

Distance is given by

d=\theta r\\\Rightarrow d=38\times 2\pi\times 0.32\\\Rightarrow d=76.4035\ m

The distance moved while slowing down is 76.4035 m

6 0
3 years ago
Read the excerpt from "Introduction to Poetry" by Billy Collins. or walk inside the poem's room and feel the walls for a light s
faust18 [17]

Answer:

D

Explanation:

Well someone has to understand the Poet Lol.

:) hope i helped

5 0
3 years ago
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