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Virty [35]
3 years ago
5

A neutron star that spins and emits beams of energy is called a _____.

Chemistry
2 answers:
3241004551 [841]3 years ago
6 0

Answer:

The correct answer is pulsar.

Explanation:

Protostar : Its a young star with contracting mass which gains mass from its parent molecular cloud. At this stage fusion process does not start.

Red dwarf:  A star having lower surface temperature , luminosity, mass and size than of the sun.

White dwarf : its an ultimate stage for an average mass star like sun . its a small dense star with size relatively equal to planet.

Pulsar :  A rotating neutron star that emits beam of radio waves and other electromagnetic radiations.

Black hole:  It is region of space time with very strong gravitational pull that even smallest particle or electromagnetic wave is incapable to escape it.

valkas [14]3 years ago
5 0
I believe its a pulsar
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What is a number at the bottom right of an element in a chemical equation called?
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Answer:

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Explanation:

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2 years ago
A 20 kg curling stone is sliding in a positive direction at 4 m/s. A second curling stone is sliding at the same speed but in th
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Answer:

The kinetic energy of the two stones is 320 J

Explanation:

Kinetic energy is the energy that a body possesses due to its movement. So it is the capacity or work that allows an object to go from being at rest, or still, to moving at a certain speed.

In other words, the kinetic energy of an object is that which is produced due to its motion and depends on its mass and velocity as follows:

Ec=\frac{1}{2} *m*v^{2}

where the kinetic energy Ec is measured in joules (J), the mass m is measured in kilograms (kg) and the velocity v in meters/second (m/s).

In this case you know that a 20 kg curling stone is sliding in a positive direction at 4 m/s. So:

  • m= 20 kg
  • v= 4 m/s

Replacing you have:

Ec_{1} =\frac{1}{2} *20 kg*(4\frac{m}{s}) ^{2}

Ec₁= 160 J

A second curling stone slides at the same speed but in the opposite direction. So:

  • m= 20 kg
  • v= - 4 m/s

Replacing you have:

Ec_{2} =\frac{1}{2} *20 kg*(-4\frac{m}{s}) ^{2}

Ec₂= 160 J

The kinetic energy of the two stones is calculated as:

Ec= Ec₁ + Ec₂

Ec= 160 J + 160 J

Ec= 320 J

<u><em>The kinetic energy of the two stones is 320 J</em></u>

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