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Arturiano [62]
3 years ago
13

Suppose you have measured the diffraction pattern of a grating with d = 0.19 mm and have found that the spots were separated by

s = 1.8 cm. Now you want to determine d for an unknown grating. With the unknown grating, the spots are separated by s = 4.5 cm. What is d (mm)?
Physics
1 answer:
cestrela7 [59]3 years ago
7 0

Answer:

d = 0.076 mm

Explanation:

Given data

diffraction pattern d1 = 0.19 mm = 0.019 cm

separated s(1)  = 1.8 cm

separated s(2) = 4.5 cm

to find out

d2 for an unknown

solution

we know here that spacing in between the diffraction fringe is always inversely proportional to diffraction grating so

we will apply here formula for unknown d that is

d1 (s1 / L) = d2 (s2 /L)

d2  = d1 ×  s(1) / s(2)

put here all thes evalue we get d2

d2  = d1 ×  s(1) / s(2)

d2  = 0.019 ×  1.8  / 4.5

d2 = 0.0076 cm

d2 = 0.076 mm

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lions [1.4K]

Answer: They will repel each other.

Explanation:

Two inflated balloons when rubbed with woolen cloth will lead to repeal each other because of the similar charges on both the balloons.

Rubbing both the balloons together by the woolen cloth will introduce negative charge in the balloons.

As, we know that the same charges repeal each other both of the balloons with be apart from each other.

This is due to the static electricity, the negatively charged particles jump to the positive one. When balloons are rubbed they become negatively charged.

3 0
4 years ago
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A ranger in a national park is driving at 56 km/h when a deer jumps onto the road 65 m ahead of the vehicle. After a reaction ti
vagabundo [1.1K]

Answer:

 t = 1.58 s

Explanation:

given,

Speed of ranger, v = 56 km/h

                            v = 56 x 0.278 = 15.57 m/s

distance, d = 65 m

deceleration,a = 3 m/s²

reaction time = ?

using stopping distance formula

d = v. t + \dfrac{v^2}{2a}

t = \dfrac{d}{v} -\dfrac{v}{2a}

t is the reaction time

t = \dfrac{65}{15.57} -\dfrac{15.57}{2\times 3}

 t = 1.58 s

hence, the reaction time of the ranger is equal to 1.58 s.

3 0
3 years ago
a body initially at rest, starts moving with a constant acceleration of 2ms-2 .calculate the velocity acquired and the distance
Marta_Voda [28]

a) 10 m/s

b) 25 m

Explanation:

a)

The body is moving with a constant acceleration, therefore we can solve the problem by using the following suvat equation:

v=u+at

where

u is the initial velocity

v is the final velocity

a is the acceleration

t is the time

For the body in this problem:

u = 0 (the body starts from rest)

a=2 m/s^2 is the acceleration

t = 5 s is the time

So, the final velocity is

v=0+(2)(5)=10 m/s

b)

In this second part, we want to calculate the distance travelled by the body.

We can do it by using another suvat equation:

v^2-u^2=2as

where

u is the initial velocity

v is the final velocity

a is the acceleration

s is the distance travelled

Here we have

u = 0 (the body starts from rest)

a=2 m/s^2 is the acceleration

v = 10 m/s is the final velocity

Solving for s,

s=\frac{10^2-0^2}{2(2)}=25 m

3 0
3 years ago
What is the thermal efficiency of a gas power cycle using thermal energy reservoirs at 627°C and 90°C?
vlada-n [284]

Answer:

The value is \eta = 63\%

Explanation:

Generally the thermal efficiency is mathematically represented as

\eta =  1 -  \frac{T_L}{T_H} * 100

substituting  [ 627°C + 273  =  900K ]  for  T_H and    [ 90°C + 273  =  333K ]  for T_L

   So  

         \eta =  1 -  \frac{333}{900} *100

=>     \eta = 63\%

5 0
3 years ago
If the sun is scaled down to 9.5 inches in diameter, the earth would be about _____ inches in diameter
vovangra [49]

Answer: 0.087 inches

Explanation:

This problem can be solved applying the <u>Rule of three</u>, which is a  mathematical rule to find out an amount that is with another quantity given in the same relation as other two also known.

In this sense, the actual diameter of the Sun is 1,391,020 km and the actual diameter of the Earth is 12,742 km.

Now, applying the <u>Rule of three:</u>

<u />

Sun 1,391,020 km ------ 9.5 inches

Earth 12,742 km --------- ? inches

? inches=\frac{(12,742 km)(9.5 inches)}{1,391,020 km}

? inches=0.087 inches

Therefore:

If the sun is scaled down to 9.5 inches in diameter, the earth would be about <u>0.087 inches </u>in diameter.

7 0
3 years ago
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