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Tanzania [10]
3 years ago
7

What is the volume, in liters, of 6.8 mol of Kr gas at STP?

Chemistry
1 answer:
Virty [35]3 years ago
6 0

Answer:

\boxed {\boxed {\sf D. \ 152 \ L}}

Explanation:

Any gas at standard temperature and pressure (STP) has a volume of 22.4 liters per mole or 22.4 L/mol. We can create a proportion with this value.

\frac {22.4 \ L \ Kr}{1 \ mol \ Kr}

Multiply both sides of the equation by 6.8 moles of krypton.

6.8 \ mol \ Kr *\frac {22.4 \ L \ Kr}{1 \ mol \ Kr}

The units of moles of krypton will cancel.

6.8 *\frac {22.4 \ L \ Kr}{1 }

The denominator of 1 can be ignored, so this becomes a simple multiplication problem.

68 * 22.4 \ L \ Kr

152.32 \ L \ Kr

If we round to the nearest whole number, the 3 in the tenths place tells us to leave the 2 in the ones place.

152 \ L \ Kr

6.8 moles of krypton gas at standard temperature and pressure is equal to <u>152 liters</u>.

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Answer: There are 145 \times 10^{23} atoms in 24 moles of Fe.

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Therefore, atoms present in 24 moles of Fe are calculated as follows.

24 mol \times 6.022 \times 10^{23} atoms/mol\\= 144.52 \times 10^{23} atoms\\or,  145 \times 10^{23} atoms

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