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3 years ago

What is the volume, in liters, of 6.8 mol of Kr gas at STP?

Chemistry

1 answer:

Virty [35]3 years ago

6 0

Answer:

$\boxed {\boxed {\sf D. \ 152 \ L}}$

Explanation:

Any gas at standard temperature and pressure (STP) has a volume of 22.4 liters per mole or 22.4 L/mol. We can create a proportion with this value.

$\frac {22.4 \ L \ Kr}{1 \ mol \ Kr}$

Multiply both sides of the equation by 6.8 moles of krypton.

$6.8 \ mol \ Kr *\frac {22.4 \ L \ Kr}{1 \ mol \ Kr}$

The units of moles of krypton will cancel.

$6.8 *\frac {22.4 \ L \ Kr}{1 }$

The denominator of 1 can be ignored, so this becomes a simple multiplication problem.

$68 * 22.4 \ L \ Kr$

$152.32 \ L \ Kr$

If we round to the nearest whole number, the 3 in the tenths place tells us to leave the 2 in the ones place.

$152 \ L \ Kr$

6.8 moles of krypton gas at standard temperature and pressure is equal to 152 liters.

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Answer: The chemical equations are given below.

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By Stoichiometry of the reaction:

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For b: NaOH is added to a solution of $Fe(NO_3)_3$

The chemical equation follows:

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By Stoichiometry of the reaction:

1 mole of iron nitrate reacts with 3 moles of sodium hydroxide to produce 1 mole of iron hydroxide and 3 moles of sodium nitrate.

For c: $FeSO_4$ is added to an acidic solution of $KMnO_4$

The chemical equation follows:

$10FeSO_4+2KMnO_4+8H_2SO_4\rightarrow 5Fe_2(SO_4)_3+K_2SO_4+2MnO_4+8H_2O$

By Stoichiometry of the reaction:

10 moles of iron(II) sulfate reacts with 2 moles of potassium permangante and 8 moles of sulfuric acid to produce 5 moles of iron(III) sulfate, 1 mole of potassium sulfate, 2 moles of manganese oxide and 8 moles of water.

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The chemical equation follows:

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By Stoichiometry of the reaction:

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