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3 years ago

What is the volume, in liters, of 6.8 mol of Kr gas at STP?

Chemistry

1 answer:

Virty [35]3 years ago

6 0

Answer:

$\boxed {\boxed {\sf D. \ 152 \ L}}$

Explanation:

Any gas at standard temperature and pressure (STP) has a volume of 22.4 liters per mole or 22.4 L/mol. We can create a proportion with this value.

$\frac {22.4 \ L \ Kr}{1 \ mol \ Kr}$

Multiply both sides of the equation by 6.8 moles of krypton.

$6.8 \ mol \ Kr *\frac {22.4 \ L \ Kr}{1 \ mol \ Kr}$

The units of moles of krypton will cancel.

$6.8 *\frac {22.4 \ L \ Kr}{1 }$

The denominator of 1 can be ignored, so this becomes a simple multiplication problem.

$68 * 22.4 \ L \ Kr$

$152.32 \ L \ Kr$

If we round to the nearest whole number, the 3 in the tenths place tells us to leave the 2 in the ones place.

$152 \ L \ Kr$

6.8 moles of krypton gas at standard temperature and pressure is equal to <u>152 liters</u>.

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Answer:

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2 years ago

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Explanation:

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12. A voltaic cell consists of a chromium electrode dipped in a 1.20 M chromium (III) nitrate

Lilit [14]

For a voltaic cell consisting of chromium, an electrode dipped in a 1.20 M chromium (III) nitrate solution and a tin electrode dipped in a 0.400 M tin (II) nitrate solution, the cell potential at 298 K is mathematically given as

Ecell = 0.577 V

<h3 /><h3>What is the cell potential at 298 K?</h3>

Generally, the equation for the Oxidation and Reduction is mathematically given as

Cr(s) ------------------ Cr+3(aq) + 3e- ] x 2 ...O

Sn+2(aq) + 2e- ------------ Sn(s) ] x 3 ...R

Reaction

2 Cr(s) + 3 Sn+2(aq) --------------- 2 Cr+3(aq) + 3 Sn(s)

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