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Olin [163]
3 years ago
7

How far away is a cliff if an echo is heard 0.486 s after the original sound? Assume that sound traveled at 343 m/s on that day.

Physics
1 answer:
goldfiish [28.3K]3 years ago
4 0
143m/s if you just perhaps by what you know you'll figure it out
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olga_2 [115]

Potential energy is the store she energy from an object this could include rubber bands. Kinetic energy is the energy that deals with motion a good example is a person running

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energy can be transfered from one type to anogher in any convection some of the energy is lost ti the enviornment as
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<span>Energy can be transformed from one type to another in any convection. Some of the energy is lost to the environment as HEAT.</span>
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The distance between two electric pole is 800m then express this in terms of mm​
Lana71 [14]

Answer:

Mm stands for milimetres

Explanation:

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One object is thrown vertically upward with an initial velocity of 100 m/s and
gavmur [86]

We have that for the Question it can be said that The maximum height reached  by the first <em>object</em> will be  100 times  that of the other.

  • (H_{max})_1=100*(H_{max})_2

From the question we are told

One object is thrown vertically upward with an initial velocity of 100 m/s and  another object with an initial velocity of 10 m/s. The maximum height reached  by the first object will be

that of the other.

a. 10,000 times

b. none of these

<em>c. </em><em>1000 times</em>

d. 100 times

<em>e.</em><em> 10 times</em>

Generally the equation for the velocity is mathematically given as

v=\frac{d}{t}\\\\Where\\\\\frac{H_{max}_1}{H_{max}_2}=\frac{(V_1)^2}{(v_2)^2}\\\\\frac{H_{max}_1}{H_{max}_2}=\frac{10000}{(10}\\\\

(H_{max})_1=100*(H_{max})_2

Therefore

The maximum height reached  by the first <em>object</em> will be  100 times  that of the other.

(H_{max})_1=100*(H_{max})_2

For more information on this visit

brainly.com/question/23379286

8 0
3 years ago
During a hurricane, the atmospheric pressure inside a house may blow off the roof because of the reduced pressure outside. If ai
m_a_m_a [10]

Answer:

817.5 Pa

Explanation:

From Bernoulli's equation, considering thst there is no height difference then

P1+½d(v1)²=P2+½d(v2)²

P1-P2=½d(v2²-v1²)

∆P=½d(v2²-v1²)

Where P represent pressure, d is density and v is velocity. Subscripts 1 and 2 represent inside and outside. ∆P is tge change in pressure

Given the speed at roof top as 128 km/h, we convert it to m/s as follows

128*1000/3600=35.555555555555=35.56 m/s

Velocity at the bottom of roof is 0 m/s

Density is given as 1.293 kg/m³

∆P=½*1.293*(35.56²-0)=817.5 Pa

5 0
3 years ago
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