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trasher [3.6K]
3 years ago
15

Graphing required Help me ASAP 4)

Mathematics
1 answer:
kicyunya [14]3 years ago
6 0
The reflection of the point (x,y) across the x-axis is the point (x,-y), so take the coordinates of each point and change them accordingly then graph them.

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Solve for x: 4x - 2 &gt; 6x + 8. (5 points)<br> x&lt;-5<br> x&gt;5<br> x&lt;5<br> x&gt;-5
alexgriva [62]

Answer:

x<-5 is the correct answer

6 0
3 years ago
Find the area of each parallelogram plz help
xxTIMURxx [149]
Answer:  The area of the parallelogram is:
_______________________________________________________
\frac{9393}{8}  in² = 1174 ⅛  in² = 1174.125 in² .
_______________________________________________________
Explanation:
_______________________________________________________
Area of a parallelogram:
_______________________________________________________
 A = base * height = b * h ;

From the figure (from the actual "question"):
_______________________________________
         b = 50.5 in.

         h = 23.25 in.
____________________________________________________________
Method 1)  A = b * h =
                 
                     =  (50.5 in) * (23.25 in) = 1174.125 in² ; or, write as:  1174 <span>⅛ .
</span>____________________________________________________________
Method 2)  A = b * h =
             
                      =  (50 ½ in) * (23 <span>¼ in) =
   
                      =    (</span>\frac{101}{2} in) * (\frac{93}{4}<span> in) ;
</span>___________________________________________________________
Note:  "50 ½ " = [(50*2) + 1 ] / 2  = \frac{101}{2} ;

Note:  "23 ¼ " = [(23*4) + 1 ] / 4  = \frac{93}{4} ;
____________________________________________________________
→  A =  (\frac{101}{2} in) * (\frac{93}{4} in) ;
 
→  A = \frac{(101*93)}{(2*4)}  in² = \frac{9393}{8}  in² ; 
          
→  A = (9393/8) in² =  
         
→  A  = \frac{9393}{8}  in² = 1174 ⅛  in² = 1174.125 in² .
________________________________________________________
5 0
3 years ago
identify the type i error and the type ii error that corresponds to the given hypothesis. the proportion of people who write wit
djverab [1.8K]

Type I error is:

" Reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually 0.29 "

Type II error is:

"Fail to reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually different from 0.29 "

<u>What is proportion?</u>

An equation in which two ratios are made equal is called a proportion. For instance, you could write the ratio as 1: 3 (for every one boy, there are three girls), which means that 14 of the population is made up of boys and 34 of the population is made up of girls.

In Statistics, a  type I error is the rejection of a true null hypothesis

and  a type II error is the non-rejection of a false null hypothesis

Given that p = 0.29 is accepted

Now type I error is

C. Reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually 0.29

i.e. (false positive)

and type II error here is

B. Fail to reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually different from 0.29.

To learn more about the proportion from the given link

brainly.com/question/19994681

#SPJ4

3 0
1 year ago
Mr. Simpson deposits his money in a savings account at the Springfield Bank. Would he earn more money with simple interest or wi
allochka39001 [22]

Answer:

THE ANSWER IS D

Step-by-step explanation:

8 0
3 years ago
Use the quadratic formula to find the solutions for..<br> y = 2x^2 - 9x + 5.
Yakvenalex [24]

Answer: x=\frac{9}{4}-\frac{\sqrt{41} }{4}  \\x=\frac{9}{4}+\frac{\sqrt{41} }{4}

Step-by-step explanation:

2x^2-9x+5

a=2

b=-9

c=5

x=\frac{-b\frac{+}{}\sqrt{b^2-4ac}  }{2a}

x=\frac{-(-9)\frac{+}{}\sqrt{(-9)^2-4(2)(5)}  }{2(2)}

x=\frac{9\frac{+}{}\sqrt{81-40}  }{4}

x=\frac{9\frac{+}{}\sqrt{41}  }{4}

x=\frac{9}{4}-\frac{\sqrt{41} }{4}  \\x=\frac{9}{4}+\frac{\sqrt{41} }{4}

4 0
3 years ago
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