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tigry1 [53]
3 years ago
8

What is the reason that the moon looks dimmer before eclipse? Why does it take some time to be brighter again after eclipse?​

Physics
2 answers:
ANTONII [103]3 years ago
4 0

Answer: The moon looks dimmer before lunar eclipse because the moon enters into shadow of penumbra region of earth. As a result, the brightness of moon decreases and looks dimmer.

Explanation:

wel3 years ago
3 0

Answer:

Why does it take sometimes to be brighter again after eclipse? The moon looks dimmer before lunar eclipse because the moon enters into shadow of penumbra region of earth. As a result, the brightness of moon decreases and looks dimmer.

Explanation:

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PLEASE HELP WITH EXPLANATION! I WILL GIVE YOU BRAINLIEST!
DiKsa [7]

Answer:

divide the distance by the time and get average velocity in units of s. the detection to the left

6 0
3 years ago
The Event Horizon Telescope needs a 22 micro-arcsecond resolution to view the event horizon regions around black holes. If the a
likoan [24]

Answer:

14869817.395 m

Explanation:

\theta=22 microarcsecond

λ = Wavelength = 1.3 mm

Converting to radians we get

22\times 10^{-6}\frac{\pi}{180\times 3600}\ radians

From Rayleigh Criterion

\theta=1.22\frac{\lambda}{D}\\\Rightarrow D=1.22\frac{\lambda}{\theta}\\\Rightarrow D=1.22\frac{1.3\times 10^{-3}}{22\times 10^{-6}\frac{\pi}{180\times 3600}}\\\Rightarrow D=14869817.395\ m

Diameter of the effective primary objective is 14869817.395 m

It is not possible to build one telescope with a diameter of 14869817.395 m. But, we need this type of telescope. So, astronomers use an array of radio telescopes to achieve a virtual diameter in order to observe objects that are the size of supermassive black hole's event horizon.

7 0
3 years ago
The gravitational acceleration on Mars is 3.71 m/s2. If the pendulums were set in motion on the red planet, how would that affec
Elanso [62]
On Earth, the period of a pendulum is given by:
T_{earth}=2\pi  \sqrt{ \frac{L}{g_{earth} }
where L is the length of the pendulum and g_{earth}=9.81~m/s^2 is the gravitational acceleration on Earth.
Similarly, the period of the same pendulum on Mars will be
T_{mars}=2\pi \sqrt{ \frac{L}{g_{mars} }
where g_{mars}=3.71~m/s^2 is the gravitational acceleration on Mars.
Therefore, if we want to see how does the period of the pendulum on Mars change compared to the one on Earth, we can do the ratio between the two of them:
\frac{T_{mars}}{T_{earth}}= \sqrt{ \frac{g_{earth}}{g_{mars}} }  =  \sqrt{ \frac{9.81~m/s^s}{3.71~m/s^2} }=1.63
Therefore, the period of the pendulum on Mars will be 1.63 times the period on Earth.
6 0
4 years ago
A car traveling at 100km/hr .how many hours will it take to cover a distance of 750 km
grin007 [14]

Answer:

7.5 right?

Explanation: if im wrong shoot me

4 0
3 years ago
Read 2 more answers
a brass spring weighs .83 Newtons while it is suspended in the air. next you immerse the ring in a container of light corn syrup
jasenka [17]

The force of gravity on the object is the same all the time ... doesn't matter
whether it's in the air, in a box, or in corn syrup.

So when it's in corn syrup, the <u>difference</u> must be the buoyant force.

  0.83N - 0.71N = <em>0.12 Newton</em>

I'm sorry, but I just have to say how disappointed I am that you couldn't
get through this one on your own.


7 0
3 years ago
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