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3 years ago

What is the percent of oxygen in the compound Mnz(S2O3)3

1 answer:

8 0

Elemental composition of Fe2(S2O3)3
Element Symbol Mass percent
Iron Fe 24.9267
Sulfur S 42.9370
Oxygen O 32.1363
Hope this helps!

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When magnesium ion doesn't give any characteristics colour with the flame test as electronic transisitons do not give out visible light.

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An ice cube at 0 degrees Celsius is heated until it melts and the water reaches 20 degrees Celsius. The amount if heat needed fo

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20 i guess

Explanation:

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3 years ago

Methyl salicylate is a common active ingredient in liniments such as ben-gay. It is also known as oil of wintergreen. It is made

arlik [135]

Answer: The empirical formula is $C_3H_3O$ .

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2$ = 12.24 g

Mass of $H_2O$ = 2.505 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 12.24 g of carbon dioxide, = $\frac{12}{44}\times 12.24=3.338g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 2.505 g of water, = $\frac{2}{18}\times 2.505=0.278g$ of hydrogen will be contained.

Mass of oxygen in the compound = (5.287) - (3.338+0.278) = 1.671 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{3.338g}{12g/mole}=0.278moles$

Moles of H= $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.278g}{1g/mole}=0.278moles$

Moles of O= $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{1.671g}{16g/mole}=0.104moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{0.278}{0.104}=3$

For H = $\frac{0.278}{0.104}=3$

For O = $\frac{0.104}{0.104}=1$

The ratio of C : H : O = 3: 3: 1

Hence the empirical formula is $C_3H_3O$ .

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3 years ago

Antique paintings will deteriorate more rapidly in a humid environment. Art museums will combat this by placing a desiccant into

stira [4]

233.1g

Explanation:

Given:

Formula units of FeCl₃ = 8.65 x 10²³ formula units

Unknown:

Mass of the FeCl₃ = ?

Solution:

The formula unit is the same as the amount of subatomic particles in an atom.

1 mole of a substance = 6.02 x 10²³ formula units

For 8.65 x 10²³ formula units; the number of moles;

Number of moles = $\frac{8.65 x 10 ^{23} }{6.02 x 10^{23} }$ = 1.44moles

Now to find the mass of FeCl₃;

Mass of FeCl₃ = 1.44 x 162.2 = 233.1g

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

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3 years ago

What is the name of the following chemical compound?

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Answer: Dinitrogen pentoxide

Explanation:

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3 years ago

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What is the percent of oxygen in the compound Mnz(S2O3)3​

What is the percent of oxygen in the compound Mnz(S2O3)3