Answer:
0.25 g of U-235 isotope will left .
Formula used :
where,
N = amount of U-235 left after n-half lives = ?
= Initial amount of the U-235 = 1.00 g
n = number of half lives passed = 2
0.25 g of U-235 isotope will left .
<h3>Answer:</h3>
Have a <em>strong</em><em> </em><em><u>polar</u></em><em><u> </u></em><em><u>attractio</u></em><em><u>ns</u></em><em><u> </u></em>between <em><u>molecule</u></em><em><u>'s</u></em><em><u> </u></em><em><u> </u></em><em><u>involvin</u></em><em><u>g</u></em><em><u> </u></em><em><u>H</u></em><em><u>,</u></em><em><u> </u></em><em><u>F</u></em><em><u>,</u></em><em><u> </u></em><em><u>O</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>N</u></em><em><u>.</u></em>
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<em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>help</u></em><em><u>s</u></em>
Answer : The structural formulas for each of the possible isomers of n-hexene are shown below.
Explanation :
Isomer : It is defined as a molecule have the same molecular formula but the different chemical structure.
There are three structural isomers of n-hexene that is based on the location of the double-bonded carbon atoms with the other atoms.
In n-hexane, 'n' shows that the chain should be straight chain there is no branching.
The three structural isomers of n-hexene are:
(1) 1-hexene
(2) 2-hexene
(3) 3-hexene
Thus, the structural formulas for each of the possible isomers of n-hexene are shown below.
Both have a continuous light spectra the fluorescent source makes a spectra with more intense bands of mercury
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Answer: The mass of silver is 1.19 X 10^14 M g
Explanation: The volume of the truck is 402 cubic feet or 1.138 x 10⁷ mm.
The density of silver is 10.49 g/mL.
We need to find the mass of silver that will fit in this moving truck. Density equals mass divided by volume. So,
<h2>
d= m/v where m= mass m= d x V</h2><h2>
M=10.49 g/mL X 1.138 X 10∧7 mL</h2>
M=119376200 g 1 gram=10⁻⁶ Megagram 119376200= 1.19 X 10^14 Mg hence the mass of silver is 1.19 X 10^14 M g hopefully this will help you please mark me as brainlist