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Rzqust [24]
3 years ago
13

Suppose you were to quickly throw a ball in outer space. Would it slow down as quickly in space, as it does in Earth? Explain wh

y, or why not.
Chemistry
1 answer:
Sholpan [36]3 years ago
7 0

Answer:It would never stop until something hit the ball, to slow it down.

Explanation:

This is so because there is no gravitational pull in space.

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Express in scientific notation. Make sure your answer has the same number of significant figures as the starting value. (1.8 x 1
slamgirl [31]

Answer : The answer is, 0.2\times 10^{-4}

Explanation :

Scientific notation : It is defined as the way or representation of expressing the number that are too big or too small that is written in the decimal form. That means always written in the power of 10 form.

For example : 8000 is written as, 8.0\times 10^3  in this notation, the significant figure is, 1 but 0.8\times 10^4  in this notation, the significant figures are, 2

The given problem are :

\frac{1.8\times 10^{-2}}{9\times 10^2}=0.2\times 10^{-4}

According to the divide and multiplication rules of scientific figures, the final answer is only as precise as the value with the least number of significant figures.

Hence, the answer is, 0.2\times 10^{-4}

6 0
3 years ago
Read 2 more answers
What is atomic mass of an element stands for
Dovator [93]
Mass is a basic property of matter and is made of atoms. Atoms are made of electrons, protons, and neutrons. Protons and neutrons make up the majority of the mass in an atom. Atoms may vary in the number of neutrons they have (called isotopes), and therefore the exact atomic mass may vary from atom to atom
3 0
3 years ago
A 0.055 mol sample of formaldehyde vapor, CH2O, was placed in a heated 500 mL vessel and some of it decomposed. The reaction is
Elis [28]

Answer:

Kc for this reaction is 0.06825

Explanation:

Step 1: Data given

Number of moles formaldehyde CH2O = 0.055 moles

Volume = 500 mL = 0.500 L

At equilibrium, the CH2O(g) concentration = 0.051 mol

Step 2: The balanced equation

CH2O  <=>  H2 + CO

Step 3: Calculate the initial concentrations

Concentration = moles / volume

[CH2O] = 0.055 moles . 0.500 L

[CH2O] = 0.11 M

[H2] = 0M

[CO] = 0M

Step 4: The concentration at the equilibrium

[CH2O] = 0.11 - X M = 0.051 M

[H2] = XM

[CO] = XM

[CH2O] = 0.11 - X M = 0.051 M

X = 0.11 - 0.051 = 0.059

[H2] = XM = 0.059 M

[CO] = XM = 0.059 M

Step 5: Calculate Kc

Kc = [H2][CO]/[CHO]

Kc = (0.059 * 0.059) / 0.051

Kc = 0.06825

Kc for this reaction is 0.06825

7 0
3 years ago
When adenosine triphosphate (ATP) releases the energy it carries, it typically breaks apart into _____.
ddd [48]
Answer:

Adenosine diphosphate (ADP) and inorganic phosphate
8 0
3 years ago
What is the chemical name of the compound K2504?
12345 [234]

Answer:

Potassium sulfate

Explanation:

I searched it up on the internet

Can I please have a brainliest

6 0
3 years ago
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