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3 years ago

Isssssssssssssssssssssssssssssss im fat

Chemistry

1 answer:

ale4655 [162]3 years ago

6 0

Answer:

just lose it then lol

Explanation:

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Which metallic properties are caused by atoms rolling over each other in metallic bonds?

Pani-rosa [81]

<span>The metallic properties that are caused by atoms rolling over each other in metallic bonds are malleability and ductility.the atoms that are being rolled over are delocalized electrons in the sea of electrons in the metallic bond enable them to roll over when stress is applied.</span>

4 0

3 years ago

Read 2 more answers

All + HgCl, --------> AICI,

Free_Kalibri [48]

Answer:

64.7g

Explanation:

The balanced chemical equation of this question is as follows;

AlI + HgCl2 → HgI + AlCl2

Based on the above equation, 1 mole of AlI (aluminum monoiodide) reacts to produce 1 mole of HgI (mercury iodide).

Using mole = mass/molar mass to convert mass of HgI to moles.

Molar mass of HgI = 200.59 + 127

= 327.59g/mol

Mole = 138/327.59

= 0.42mol

- If 1 mole of AlI (aluminum monoiodide) reacts to produce 1 mole of HgI (mercury iodide)

- Then 0.42 mol of HgI will be produced by 0.42mol of AlI.

Using mole = mass/molar mass

Mass = mole × molar mass

Molar mass of AlI = 27 + 127

= 154g/mol

Mass of AlI = 0.42 × 154

= 64.7g of AlI

5 0

3 years ago

How many atoms of phosphorus are in 3.30 mol of copper(II) phosphate?

otez555 [7]

Hmgmcbfbhuhhvvvuuuuuuuuuh

6 0

4 years ago

Read 2 more answers

Look at the picture

Ronch [10]

Answer:

The strong electric force.

Explanation:

Trust me. If its wrong, comment on this, don't delete it. If someone else answers with the wrong question than other students might get the answer wrong. So if its right, say that it is, if its wrong, tell others what the real answer is.

3 0

2 years ago

When 0.100 mol of carbon is burned in a closed vessel with8.00

antoniya [11.8K]

Answer : The mass of carbon monoxide form can be 2.8 grams.

Solution : Given,

Moles of C = 0.100 mole

Mass of $O_2$ = 8.00 g

Molar mass of $O_2$ = 32 g/mole

Molar mass of CO = 28 g/mole

First we have to calculate the moles of $O_2$ .

$\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{8g}{32g/mole}=0.25moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$2C+O_2\rightarrow 2CO$

From the balanced reaction we conclude that

As, 2 mole of $C$ react with 1 mole of $O_2$

So, 0.1 moles of $C$ react with $\frac{0.1}{2}=0.05$ moles of $O_2$

From this we conclude that, $O_2$ is an excess reagent because the given moles are greater than the required moles and $C$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $CO$

From the reaction, we conclude that

As, 2 mole of $C$ react to give 2 mole of $CO$

So, 0.1 moles of $C$ react to give 0.1 moles of $CO$

Now we have to calculate the mass of $CO$

$\text{ Mass of }CO=\text{ Moles of }CO\times \text{ Molar mass of }CO$

$\text{ Mass of }CO=(0.1moles)\times (28g/mole)=2.8g$

Therefore, the mass of carbon monoxide form can be 2.8 grams.

5 0

4 years ago