Question

When 5800 joules of energy are applied to a 15.2-kg piece of lead metal, how much does the temperature change by

Answer 1

Heat gained or absorbed in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. The heat capacity of aluminum at 25 degrees celsius is 0.9 J/g-C. It is expressed as follows:

Heat = mC(T2-T1)
5800 J = 152000(0.90)(ΔT)

ΔT = 0.42 °C change in temperature

Answer 2

Answer: 2.98 K

Explanation:

$Q= m\times c\times \Delta T$

Q= heat gained  or released= 5800 J

m= mass of the substance = 15.2 kg = 15200 g   (1kg=1000g)

c = heat capacity of  lead= 0.128 J/gK      

$\Delta T={\text{Change in temperature}}=?$  

$5800J=15200g\times 0.128J/gK\times \Delta T$

$\Delta T= 2.98K$

Thus change in temperature is 2.98 K.