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Arte-miy333 [17]
3 years ago
15

How many mL of solution are required to make a 0.270M solution of sodium chloride if you have 2.18g of sodium chloride?

Chemistry
1 answer:
dem82 [27]3 years ago
3 0

Answer:

138mL are required to make the solution

Explanation:

A solution of 0.270M contains 0.270 moles of solute (NaCl in this case), per liter of solution.

To solve this problem we need to determine the moles of NaCl in 2.18g. With these moles and molarity we can find the volume required to prepare the solution:

<em>Moles NaCl -Molar mass: 58.44g/mol-:</em>

2.18g * (1mol / 58.44g) = 0.0373moles NaCl

<em>Volume of solution:</em>

0.0373moles NaCl * (1L / 0.270moles) = 0.138L

<h3>138mL are required to make the solution</h3>

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In this equation, the order with respect to each reactant is not equal to its stoichiometric coefficient which is represented in the balanced chemical reaction.

Hence, this is not considered as an elementary reaction.

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Explanation:

The shapes and relative energies of the orbitals s,p,d and f orbitals are given by the principal quantum number and the azimuthal quantum number.

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L             Name of orbital                     shape of orbital

0                     s                                         spherical

1                      p                                         dumb-bell

2                     d                                        double dumb-bell

3                      f                                          complex

Principal                        Azimuthal                   Orbital

Quantum                       Quantum                    Designation of

Number (N)                  Number(l)                     Sublevel

       1                                   0                                   1s

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      4                                   0                                    4s

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Learn more:

Atomic orbitals brainly.com/question/9514863

#learnwithBrainly

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