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Step2247 [10]
2 years ago
7

Would I need Circumference or Area to calculate the distance around a circular track?

Mathematics
2 answers:
snow_lady [41]2 years ago
7 0
The circumference because its not about the interior
Hatshy [7]2 years ago
4 0

Answer:

The circumference because it's not about the interior space of the circular track but the track itself.

Hope this helped!

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Find an equation of the line in the form whose​ x-intercept is 15 and​ y-intercept is 3​, where​ a, b, and c are integers with n
madreJ [45]

x-intercept = (15, 0)                  y-intercept = (0, 3)

slope (m) = (y₂ - y₁)/(x₂ - x₁) = (0 - 3)/(15 - 0) = -3/15 = -1/5

Point-Slope formula: y - y₁ = m(x - x₁)   ; where (x₁, y₁) is one of the given points

y - 0 = (-1/5)(x - 15)

    -5y = x - 15

             x + 5y = 15

Answer: x + 5y = 15

5 0
3 years ago
Find the exact value of sin (arccos(-3/4))
Arturiano [62]
The exact value is
<span>sin<span>(arccos<span>(<span>3/4</span>)</span>)</span></span>The equation for cosine is <span>cos<span>(A)</span>=<span>AdjacentHypotenuse</span></span>. The inside trig function is <span>arccos<span>(<span>3/4</span>)</span></span>, which means <span>cos<span>(A)</span>=<span>3/4</span></span>. Comparing <span>cos<span>(A)</span>=<span>AdjacentHypotenuse</span></span> with <span>cos<span>(A)</span>=<span>3/4</span></span>, find <span>Adjacent=3</span> and <span>Hypotenuse=4</span>. Then, using the pythagorean theorem, find <span>Opposite=<span>√7</span></span>.<span>Adjacent=3</span><span>Opposite=<span>√7</span></span><span>Hypotenuse=4</span>Substitute in the known variables for the equation <span>sin<span>(A)</span>=<span>OppositeHypotenuse</span></span>.<span>sin<span>(A)</span>=<span><span>√7</span> over 4</span></span>Simplify.<span><span>√7</span><span> over 4</span></span>
6 0
3 years ago
Represent the relationship between the number of copies made and time in seconds in the table
alexdok [17]

Answer:

you need to put  the table

Step-by-step explanation:

7 0
3 years ago
A cake manufacturer boxes Swiss chocolate and German chocolate cakes at one site. A box of Swiss chocolate cake contains 0.55 lb
Kobotan [32]

Answer:

2,500 German chocolate cake boxes.

1,500 Swiss chocolate cake boxes.

Step-by-step explanation:

Let 'S' be the number of Swiss chocolate cakes boxed and 'G' the number of German cholocate cakes boxed. If all of the available ingredients are used:

0.55*S +0.59*G = 2,300\\0.45*S+0.41*G = 1,700

Solving the linear system above:

(0.55 *S +0.59*G)- \frac{0.55}{0.45} (0.45*S+0.41*G)= 2,300-\frac{0.55}{0.45}*1,700*\\0.088888*G = 222.222\\G=2,500\\S =\frac{2,300-2,500*0.59}{0.55}\\S=1500

2,500 German chocolate cake boxes and 1,500 Swiss chocolate cake boxes can be made each day.

6 0
3 years ago
Jose earned 50 points in a video game. He lost 40 points, earned 87 points, then lost 30 more pints. Write and evaluate an expre
Aneli [31]
50-40+87-30=67

hope i helped
4 0
3 years ago
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