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3 years ago

What are the characteristics of a virtual image? Check all that apply.

Chemistry

2 answers:

tia_tia [17]3 years ago

6 0

<h3>Answer:</h3>

Can only be seen while looking through a lens
May appear larger than the object
Appears to come from behind the lens

<h3>Explanation:</h3>

To answer this question we need to ask ourselves;

What is a virtual image?

A virtual image is an image that can not be formed on a screen.
It is formed by rays that appear to converge at a point.

What are the characteristics of a virtual image?

A virtual image can only be seen while looking through lenses
The image appear to come from behind the lens
It may be larger than the object
It can not be projected onto a screen.
It is always upright

pentagon [3]3 years ago

6 0

Answer:

. Can only be seen while looking through a lens

. May appear larger than the object

. Appears to come from behind the lens

Explanation:

I've got it correct on e2020

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For the following reaction, 22.9 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas. nitrogen monox

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Answer:

1) Maximun ammount of nitrogen gas: $m_{N2}=10.682 g N_2$

2) Limiting reagent: $NO$

3) Ammount of excess reagent: $m_{N2}=4.274 g$

Explanation:

<u>The reaction </u>

$2 NO (g) + 2 H_2 (g) \longrightarrow N_2 (g) + 2 H_2O (g)$

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Molecular weight: $M_{NO}=30 g/mol$

$n_{NO}=\frac{m_{NO}}{M_{NO}}$

$n_{NO}=\frac{22.9 g}{30 g/mol}=0.763 mol$

Moles of hydrogen

Molecular weight: $M_{H2}=2 g/mol$

$n_{H2}=\frac{m_{H2}}{M_{H2}}$

$n_{H2}=\frac{.5.8 g}{2 g/mol}=2.9 mol$

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1) <u>Maximun ammount of nitrogen gas</u> => when all NO reacted

$m_{N2}=0.763 mol NO* \frac{1 mol N_2}{2 mol NO}*\frac{28 g N_2}{mol N_2}$

$m_{N2}=10.682 g N_2$

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3) <u>Ammount of excess reagent</u>:

$m_{N2}=(2.9 mol - 0.763 mol NO* \frac{1 mol H_2}{1 mol NO})*\frac{2 g H_2}{mol H_2}$

$m_{N2}=4.274 g$

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