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2 years ago

What are the characteristics of a virtual image? Check all that apply.

Chemistry

2 answers:

tia_tia [17]2 years ago

6 0

<h3>Answer:</h3>

Can only be seen while looking through a lens
May appear larger than the object
Appears to come from behind the lens

<h3>Explanation:</h3>

To answer this question we need to ask ourselves;

What is a virtual image?

A virtual image is an image that can not be formed on a screen.
It is formed by rays that appear to converge at a point.

What are the characteristics of a virtual image?

A virtual image can only be seen while looking through lenses
The image appear to come from behind the lens
It may be larger than the object
It can not be projected onto a screen.
It is always upright

pentagon [3]2 years ago

6 0

Answer:

. Can only be seen while looking through a lens

. May appear larger than the object

. Appears to come from behind the lens

Explanation:

I've got it correct on e2020

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20 mL of an approximately 10% aqueous solution of ethylamine, CH3CH2NH2, is titrated with 0.3000 M aqueous HCl. Which indicator

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Answer:

Therefore, The indicator that is best fit for the given titration is Bromocresol Green Color change from pH between 4.0 to 5.6

Bromocresol green, color change from pH = 4.0 to 5.6

Explanation:

The equation for the reaction is :

$C_2H_5NH_2_(_a_q_) + H^+_(_a_q_) --- C_2H_5NH_{3(aq)}^+$

concentration of $C_2H_5NH_{2(aq)$ = 10%

10 g of $C_2H_5NH_{2(aq)$ in 100 ml solution

molar mass = 45.08 g/mol

number of moles = 10 / 45.08

= 0.222 mol

Molarity of $C_2H_5NH_2(aq) = 0.222 \times \frac{1000}{100}mL$

= 2.22 M

number of moles of $C_2H_5NH_{2(aq)$ in 20 mL can be determined as:

$= 20 mL \times 2.22 M= 44*10^{-3} mole$

Concentration of $C_2H_5NH_2(aq) = \frac{44*10^{-3}*1000}{20}$

= 2.22 M

Similarly, The pKa Value of $C_2H_5NH_{2(aq)$ is given as 10.75

pKb value will be: 14 - pKa

= 14 - 10.75

= 3.25

the pH value at equivalence point is,

$pH= \frac{1}{2}pKa - \frac{1}{2}pKb-\frac{1}{2}log[C]$

$pH = \frac{14}{2}-\frac{3.25}{2}-\frac{1}{2}log [2.22]$

$pH = 5.21$

Therefore, The indicator that is best fit for the given titration is Bromocresol Green Color change from pH between 4.0 to 5.6

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</span>

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