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Otrada [13]
3 years ago
14

What are the characteristics of a virtual image? Check all that apply.

Chemistry
2 answers:
tia_tia [17]3 years ago
6 0
<h3>Answer:</h3>
  • Can only be seen while looking through a lens
  • May appear larger than the object
  • Appears to come from behind the lens
<h3>Explanation:</h3>

To answer this question we need to ask ourselves;

What is a virtual image?

  • A virtual image is an image that can not be formed on a screen.
  • It is formed by rays that appear to converge at a point.

What are the characteristics of a virtual image?

  • A virtual image can only be seen while looking through lenses
  • The image appear to come from behind the lens
  • It may be larger than the object
  • It can not be projected onto a screen.
  • It is always upright
pentagon [3]3 years ago
6 0

Answer:

. Can only be seen while looking through a lens

. May appear larger than the object

. Appears to come from behind the lens

Explanation:

I've got it correct on e2020

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Potential energy is based on an objects <br><br> A)gravity<br> B)mass<br> C)position <br> D)kinetic
ollegr [7]

Answer:

c

Explanation:

because potential energy is created with the position of a body when you pick up something the thing will have stored energy which is transferred from you so the stored energy is potential energy created by the position of a body that when you see over your head you scared of that thing not to bit you because it has stored energy if you see the thing already failed on the ground you wouldn't scared of that because the enery is already gone

Hope help you

5 0
3 years ago
Combustion of hydrocarbons such as butane () produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Earth's atmosp
Dahasolnce [82]

Answer:

1. C₄H₁₀ + ¹³/₂O₂ → 4CO₂ + 5H₂O

2. V = 596L

Explanation:

Butane (C₄H₁₀) reacts with oxygen (O₂) to produce carbon dioxide (CO₂) and water (H₂O) thus:

C₄H₁₀ + O₂ → CO₂ + H₂O

1. The balanced chemical equation is:

C₄H₁₀ + ¹³/₂O₂ → 4CO₂ + 5H₂O

2. 0,360kg of butane are:

360g×\frac{1mol}{58,12g}=<em>6,19moles of butane</em>

These moles of butane are:

6,19moles of butane×\frac{4CO_2}{1molButane}= <em>24,8 moles CO₂</em>

Using V=nRT/P

Where:

n are moles (24,8 moles CO₂); R is gas constant (0,082atmL/molK); T is temperature, 20°C (293,15K); and P is pressure (1atm).

Volume (V) is:

<em>V = 596L</em>

I hope it helps!

8 0
3 years ago
Tiffany was investing how fast it took Hayden to react to different sounds. Identify the independent variable.
Hatshy [7]

Answer:

The different sounds

Explanation:

since it can not be changed

7 0
3 years ago
Need help on B and C please!!
puteri [66]
B. The reason the temperature experienced no change in group c is because it was likely the control group.
I cannot read question c, the monitor refresh is obscuring the text.
5 0
3 years ago
Helooo i need help please :)
Tatiana [17]
It is a ,d and c just make sure tho
6 0
2 years ago
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