Subatomic particles include electrons, the negatively charged, almost massless particles that nevertheless account for most of the size of the atom, and they include the heavier building blocks of the small but very dense nucleus of the atom, the positively charged protons and the electrically neutral neutrons.
And I don't see any of the particles. so I can only answer the first one.
Is there any multiple choices?
Answer:
We'll have 8.0 moles Fe3O4 and 4.0 moles CO2
Explanation:
Step 1: data given
Number of moles Fe2O3 = 12.0 moles
Number of moles CO = 12.0 moles
Step 2: The balanced equation
3Fe2O3 +CO → 2Fe3O4 + CO2
Step 3: Calculate the limiting reactant
For 3 moles Fe2O3 we need 1 mol CO to produce 2 moles Fe3O4 and 1 mol CO2
Fe2O3 is the limiting reactant. It will completely be consumed (12.0 moles).
CO is in excess. There will react 12.0 / 3 = 4.0 moles
There will remain 12.0 - 4.0 = 8.0 moles
Step 4: Calculate moles products
For 3 moles Fe2O3 we need 1 mol CO to produce 2 moles Fe3O4 and 1 mol CO2
For 12.0 moles Fe2O3 we'll have 2/3 * 12.0 = 8.0 moles Fe3O4
For 12.0 moles Fe2O3 we'll have 12.0 / 3 = 4.0 moles CO2
We'll have 8.0 moles Fe3O4 and 4.0 moles CO2
Answer:
Mendeleev left spaces in his periodic table because he predicted there were elements that weren't discovered yet that would fit in these spaces.
Explanation:
Considering the Boyle's law, the new pressure of the sample is 1,776 mmHg.
<h3>What is Boyle's law</h3>
Boyle's law establishes the relationship between the pressure and the volume of a gas when the temperature is constant.
Boyle's law states that the volume occupied by a given mass of gas at constant temperature is inversely proportional to the pressure. This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.
Boyle's law is expressed mathematically as:
P×V=k
Now it is possible to assume that you have a certain volume of gas V1 which is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and the following will be true:
P1×V1=P2×V2
<h3>New pressure</h3>
In this case, you know:
- P1= 740 mmHg
- V1= 3 L
- P2= ?
- V2= 1.25 L
Replacing in Boyle's law:
740 mmHg× 3 L=P2× 1.25 L
Solving:
P2= (740 mmHg× 3 L) ÷ 1.25 L
P2= 1,776 mmHg
Finally, the new pressure of the sample is 1,776 mmHg.
Learn more about Boyle's law:
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