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2 years ago

Oxygen has 8 positively-charged protons. What is the number of negatively-charged electrons in an atom of Oxygen?

Chemistry

2 answers:

Gala2k [10]2 years ago

8 0

Answer:

Answer 9: Oxygen is atomic number 8 on the periodic table, which means it has 8 protons!

Explanation:

Oxygen's 8 electrons are negatively charged, and they orbit the atomic nucleus and balance the positive charge of the 8 protons. The positive charge of 1 proton exactly cancels the negative charge of 1 electron.

8_murik_8 [283]2 years ago

4 0

8

because the positive and negative atoms always valence out.

hope this helps!

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kirza4 [7]

Answer:

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Explanation:

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2 years ago

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The absorbance of a chlorophyll a standard solution in ethanol (density = 0.785 g/mL) is measured in

Dmitry_Shevchenko [17]

Let A= ebc 
 0.765 = 86,300*1.3*c 

Solve for c = approximately 7E-6 Molar
= mols/L soln. 
g = 7E-6*893.49
= about 0.006 g chlorophyll/L soln. 

1000 x 0.785 = 785 g ethanol. 
Conc. = about 0.006g chlorophyll/785 g soln. 

Change that to ppm. by using formula:
(0.006/785)*1E6

5 0

3 years ago

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Given the following equation, what is the correct form of the conversion factor needed to convert the number of moles O2 to the

jek_recluse [69]

Answer:

Option A says we have 4 moles of Fe for each 3 moles O2

This is correct For 3 moles of O2 consumed, we need 4 moles of Fe to be reacted

Explanation:

Step 1: Data given

Step 2: The balanced equation

4Fe + 3O2 → 2Fe2O3

Step 3: Calculate the mol ratio

For 3 moles O2 we'll have 4 moles Fe

Option A says we have 4 moles of Fe for each 3 moles O2

This is correct For 3 moles of O2 consumed, we need 4 moles of Fe to be reacted

Option b says we have 2 mole Fe2O3 for each 4 moles Fe

This doesnt say anything about O2. So doesn't apply for this question.

Option C says we have 4 moles of Fe for each 2 moles Fe2O3

This is the same as option B, so doesn't apply for this question.

Option D says for each 3 moles of O2 we have 2 Fe2O3

This is true, but doesn't say anything about Fe so doesn't apply here.

4 0

3 years ago

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A sample of phosphonitrilic bromide, PNBr2, contains 2.01 mol of the compound. Determine the amount (in mol) of each element pre

nordsb [41]

Answer:

2.01 moles of P → 1.21×10²⁴ atoms

2.01 moles of N → 1.21×10²⁴ atoms

4.02 moles of Br → 2.42×10²⁴ atoms

Explanation:

We begin from this relation:

1 mol of PNBr₂ has 1 mol of P, 1 mol of N and 2 moles of Br

Then 2.01 moles of PNBr₂ will have:

2.01 moles of P

2.01 moles of N

4.02 moles of Br

To determine the number of atoms, we use the relation:

1 mol has NA (6.02×10²³) atoms

Then: 2.01 moles of P will have (2.01 . NA) = 1.21×10²⁴ atoms

2.01 moles of N (2.01 . NA) = 1.21×10²⁴ atoms

4.02 moles of Br (4.02 . NA) = 2.42×10²⁴ atoms

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3 years ago

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The following combinations are not allowed. If n and ml are correct, change the l value to create an allowable combination:

ololo11 [35]

The allowable combination for the atomic orbital is n=3, l=1 or 2, $m_{l}$ =+1.

<h3>What are the three quantum numbers of an atomic orbital?</h3>

Three quantum numbers specify an atomic orbital:

- The principal quantum number, n, which is a positive integer, describes the relative size of the orbital and its distance from the nucleus.

- l is the angular momentum quantum number that is related to the shape of the orbital; l is an integer from 0 to n-1 (so n limits l ),

- $\boldsymbol{m}_{l}$ is the magnetic quantum number that prescribes the three-dimensional shape of the orbital around the nucleus; $m_{l}$ values are integers from -l to =l(l limits ml)

For n = 3, l can have three values: 0, 1, and 2. Hence, the l value must be lower than 3. Because of $m_{l}$ = +1, the l value must be higher than 0. Two l values are consistent with n and $m_{l)$ values:

l= 1 or 2

Therefore, the allowable condition is n=7, l=1 or 2, $m_{l}$ =+3.

To know more about quantum numbers, visit: brainly.com/question/16979660

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1 year ago