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3 years ago

13

Your family is moving to a new house. While lifting the box 1.5 m straight up you exerted a force of 200 N for 1 second. How muc

h work is required?

1 answer:

AlladinOne [14]3 years ago

6 0

If you lifted 200 Newtons 1.5 meters straight up, you did 300 joules of work no matter how fast or slow you did it.

If you did it in 1 second, then you did it at the rate of 300 watts.

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A 0.877 mol sample of N2(g) initially at 298 K and 1.00 atm is held at constant volume while enough heat is applied to raise the

MissTica

Answer : The value of $q\text{ and }\Delta U$ is 286.2 J and 286.2 J respectively.

Explanation : Given,

Moles of sample = 0.877 mol

Change in temperature = 15.7 K

First we have to calculate the heat absorbed by the system.

Formula used :

$q=n\times c_v\times \Delta T$

where,

q = heat absorbed by the system = ?

n = moles of sample = 0.877 mol

$\Delta T$ = Change in temperature = 15.7 K

$c_v$ = heat capacity at constant volume of $N_2$ (diatomic molecule) = $\frac{5}{2}R$

R = gas constant = 8.314 J/mol.K

Now put all the given value in the above formula, we get:

$q=0.877mol\times \frac{5}{2}\times 8.314J/mol.K\times 15.7K$

$q=286.2J$

Now we have to calculate the change in internal energy of the system.

$\Delta U=q+w$

As we know that, work done is zero at constant volume. So,

$\Delta U=q=286.2J$

Therefore, the value of $q\text{ and }\Delta U$ is 286.2 J and 286.2 J respectively.

8 0

3 years ago

Read 2 more answers

A rocket is launched from the surface of Earth with a speed v0 that will allow the rocket to escape the gravitational field of E

weeeeeb [17]

Answer:

option ( a ) is correct .

Explanation:

Escape velocity on the earth = √ ( 2 GM / R )

where G is universal gravitational constant , M is mass of the earth and R is radius .

V₀ = √ ( 2 GM / R )

escape velocity on the planet where mass is equal is earth's mass and radius is 4 times that of the earth

Radius of the planet = 4 R

escape velocity of planet = √ ( 2 GM / 4R )

= .5 x √ ( 2 GM / R )

= .5 V₀

option ( a ) is correct .

8 0

2 years ago

Determine the binding energy per nucleon of an mg-24 nucleus. the mg-24 nucleus has a mass of 24.30506. a proton has a mass of 1

My name is Ann [436]

The mass of Mg-24 is 24.30506 amu, it contains 12 protons and 12 neutrons.

Theoretical mass of Mg-24:

The theoretical mass of Mg-24 is:

Hydrogen atom mass = 12 × 1.00728 amu = 12.0874 amu

Neutron mass = 12 x 1.008665 amu = 12.104 amu

Theoretical mass = Hydrogen atom mass + Neutron mass = 24.1913 amu

Note that the mass defect is:

Mass defect = Actual mass - Theoretical mass : 24.30506 amu- 24.1913 amu= 0.11376 amu

Calculating the binding energy per nucleon:

$\frac{B.E.}{nucleon}=\frac{(0.11376amu)(931Mev/amu}{24nucleons} = 4.41294 Mev/nucleon$

So approximately 4.41294 Mev/necleon

3 0

2 years ago

Which term best describes the form of beryllium shown

astra-53 [7]

Answer:

✓ Ion

Explanation:

Which term BEST describes the form of beryllium shown? Protons=4 Neutrons=5 Electrons=2

✓ Ion

3 0

2 years ago

A roller coaster has a "hump" and a "loop" for riders to enjoy (see picture). The top of the hump has a radius of curvature of 1

nikklg [1K]

Answer:

Part a)

$F_n = 306 N$

Part B)

$v = 12.1 m/s$

Explanation:

Part A)

At the top of the hump the force on the rider is

1) Normal force

2) weight

so here we know that

$mg - F_n = \frac{mv^2}{R}$

$F_n = mg - \frac{mv^2}{R}$

$F_n = (100)(9.81) - \frac{100(9^2)}{12}$

$F_n = 306 N$

Part B)

At the top of the loop we will have

$F_n + mg = \frac{mv^2}{R}$

in order to remain in contact the normal force must be just greater than zero

so we will have

$mg = \frac{mv^2}{R}$

$v = \sqrt{Rg}$

$v = \sqrt{15\times 9.81}$

$v = 12.1 m/s$

5 0

3 years ago