Answer: 0.85075J/g.K
Explanation:
Mass of the material = 100g
Energy (Q) = 5104.5J
T1 = 20°C = 293K
T2 = 80°C = 353K
Formula for heat energy (Q) = mc ∇T
Q = mc∇T
∇T = T2 - T1
∇T = 353K - 293K = 60K
Q = mc∇T
C = Q / m∇T
C = (5104.5) / (100 * 60)
C = 0.85075 J/gK
The specific heat capacity of the material is 0.85075J/gK.
Answer: I think the formula is PV=nRT and I divide both sides by RT, but this is as far as I can get in my equation before I get stumped: (751 mm Hg) (8.3 L)/ (309 K) Can you help?
Explanation:
Answer: Approximately 
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Work Shown:
We have the following variables
- Q = 714 joules = heat required
- m = 52 grams = mass
- c = specific heat = unknown
= 82-30.5 = 51.5 = change in temperature
note: the symbol 
is the uppercase Greek letter delta. It represents the difference or change in a value.
Apply those values into the formula below. Solve for c.
The specific heat of the unknown metal is roughly
Answer: D is ur answer
Hope it helps chu!
Have a good day, My fellow bean UwU
