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Alexxandr [17]
2 years ago
15

How far moves in 95g ball by applying 200 Newton Force if 14 KJ of energy is transferred​

Physics
1 answer:
Sunny_sXe [5.5K]2 years ago
3 0

Answer.....

Explanation:

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According to the Heisenberg uncertainty principle, if the uncertainty in the speed of an electron is 3.5 × 103 m/s, the uncertai
GREYUIT [131]

Explanation:

It is given that,

Uncertainty in the speed of an electron, \Delta v=3.5\times 10^3\ m/s

According to Heisenberg uncertainty principle,

\Delta x.\Delta p=\dfrac{h}{4\pi}

\Delta x is the uncertainty in the position of an electron

Since, \Delta p=m\Delta v

\Delta x=\dfrac{h}{4\pi.m \Delta v}

\Delta x=\dfrac{6.6\times 10^{-34}}{4\pi\times 9.1\times 10^{-31}\times 3.5\times 10^3}

\Delta x=1.64\times 10^{-8}\ m

So, the uncertainty in its position is 1.64\times 10^{-8}\ m. Hence, this is the required solution.

6 0
3 years ago
PLEASE HELP ME (stop putting links ) Two objects m1 and m2, each with a mass of 5 kg and 6 kg separated by a distance. A third o
BabaBlast [244]

Answer:

Explanation:

Newton's Gravitation Law

\displaystyle \frac{GmM}{d^2}

where G is a constant, M and M the masses e d the distance betwen masses.

\displaystyle G\frac{5\cdot2}{x^2}=G\frac{6\cdot 2}{(2x+1)^2} \quad \sqrt{6}x=(2x+1)\sqrt {5} \quad x=\frac{\sqrt{5}}{\sqrt{6}-2\sqrt{5}}

7 0
3 years ago
In the following circuit, the supplied voltage is 1.5 volts and the resistor value is 2 ohms. Use Ohm's law to determine the cur
attashe74 [19]

Answer:

0.75 Amps

Explanation:

I had this question and this was right

7 0
3 years ago
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What happens when a force is applied to an object in stable equilibrium
Katarina [22]

Answer:

the object is no longer in equilibrium .

7 0
3 years ago
An average human weighs about 600 N
NemiM [27]

Answer:

The distance between them, x = 5809.47 m

Explanation:

Given,

The average weight of a human, w = 600 N

The charge carried by the humans, q = 1.5 C

If 600 N of force acts between two opposite charges, the distance between the charges can be derived from the Coulomb's laws of force,

                          <em>F=\frac{1}{4\pi\epsilon_{0}}\frac{qq}{x^{2}}</em>

Where,

                         \frac{1}{4\pi\epsilon_{0}} = 9 x 10⁹ N m² C⁻²

Therefore

                          x² = 9 x 10⁹ X 1.5² / 600

                              = 33750000

                           x = 5809.46 m

Hence, the distance between the humans should be, x = 5809.47 m

4 0
3 years ago
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