An average human weighs about 600 N
1 answer:
Answer:
The distance between them, x = 5809.47 m
Explanation:
Given,
The average weight of a human, w = 600 N
The charge carried by the humans, q = 1.5 C
If 600 N of force acts between two opposite charges, the distance between the charges can be derived from the Coulomb's laws of force,
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Where,
= 9 x 10⁹ N m² C⁻²
Therefore
x² = 9 x 10⁹ X 1.5² / 600
= 33750000
x = 5809.46 m
Hence, the distance between the humans should be, x = 5809.47 m
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Answer:
J = 357.5 kg*m/s
Explanation:
- The impulse exerted on Katelyn when she was on the force plate, is equal to the change in her momentum, according to Newton's 2nd Law.
- Assuming as the positive direction the upward direction (coincident with the positive y-axis) we can express the initial momentum as follows:
- By the same token, the final momentum is as follows:
- As we have already said, the impulse J is just equal to the change in momentum, i.e., the difference between (2) and (1):
I assume L=120 yards as the length of the football field.
1) The average speed is given by the total distance covered by the player divided by the time taken.
The total distance covered to go from one goal line to the other and then back to the 40-yards line is
And the time taken is t=22.4 s, so the average speed of the player is
2) The find the average velocity, we should also consider the direction (and the sign) of the velocity.
In the the first part of the motion, the player goes from one goal line to the other one, so he covers 120 y. However, in the second part of the motion he goes back by 80 y. Therefore, the net displacement of the player is
and so, the average velocity is
1) The average speed is given by the total distance covered by the player divided by the time taken.
The total distance covered to go from one goal line to the other and then back to the 40-yards line is
And the time taken is t=22.4 s, so the average speed of the player is
2) The find the average velocity, we should also consider the direction (and the sign) of the velocity.
In the the first part of the motion, the player goes from one goal line to the other one, so he covers 120 y. However, in the second part of the motion he goes back by 80 y. Therefore, the net displacement of the player is
and so, the average velocity is