Answer:
125
Explanation:
All I did was simple math. According to the question it tells us that, "Power = (Distance * Force) / Time Conversion rate" so with that information I multiplied '150 feet' (Distance) * '50lbs' (Force) which equals 7500, then I divided that number by '60 seconds' (Time Conversion rate) and got the number, 125 which seems to be the answer.
Answer:
a) Decreasing grain size decreases the amount of possible pile up at the boundary, increasing the amount of applied stress necessary to move a dislocation across a grain boundary. ... Grain sizes can range from about 100 μm (0.0039 in) (large grains) to 1 μm (3.9×10−5 in) (small grains).
b) Solid solution strengthening is a type of alloying that can be used to improve the strength of a pure metal. The technique works by adding atoms of one element (the alloying element) to the crystalline lattice of another element (the base metal), forming a solid solution.
c) Work hardening, also known as strain hardening, is the strengthening of a metal or polymer by plastic deformation. ... This strengthening occurs because of dislocation movements and dislocation generation within the crystal structure of the material.
Explanation:
I hope this will help you bro/sis
Given :
To Find :
The general solution of the given equation.
Solution :
We know, 
Comparing it with given equation, we get :
General solution is given by :
where n ∈ Z ( integers )
Hence, this is the required solution.
Answer: u slap birds
Explanation: u order cheeseburgers with n cheese
Answer:
D) 1.04 Btu/s from the liquid to the surroundings.
Explanation:
Given that:
flow rate (m) = 2 lb/s
liquid specific enthalpy at the inlet (
Btu/lb)
liquid specific enthalpy at the exit (
Btu/lb)
initial elevation (
)
final elevation (
)
acceleration due to gravity (g) = 32.174 ft/s²
= 3 Btu/s
The energy balance equation is given as:
![Q_{cv}-W{cv}+m[(h_1-h_2)+(\frac{V_1^2-V_2^2}{2})+g(z_1-z_2)]=0](https://tex.z-dn.net/?f=Q_%7Bcv%7D-W%7Bcv%7D%2Bm%5B%28h_1-h_2%29%2B%28%5Cfrac%7BV_1%5E2-V_2%5E2%7D%7B2%7D%29%2Bg%28z_1-z_2%29%5D%3D0)
Since kinetic energy effects are negligible, the equation becomes:
![Q_{cv}-W{cv}+m[(h_1-h_2)+g(z_1-z_2)]=0](https://tex.z-dn.net/?f=Q_%7Bcv%7D-W%7Bcv%7D%2Bm%5B%28h_1-h_2%29%2Bg%28z_1-z_2%29%5D%3D0)
Substituting values:
![Q_{cv}-(-3)+2[(40.09-40.94)+\frac{32.174(0-100)}{778*32.174} ]=0\\Q_{cv}+3+2[-0.85-0.1285 ]=0\\Q_{cv}+3+2(-0.9785)=0\\Q_{cv}+3-1.957=0\\Q_{cv}+1.04=0\\Q_{cv}=-1.04\\](https://tex.z-dn.net/?f=Q_%7Bcv%7D-%28-3%29%2B2%5B%2840.09-40.94%29%2B%5Cfrac%7B32.174%280-100%29%7D%7B778%2A32.174%7D%20%5D%3D0%5C%5CQ_%7Bcv%7D%2B3%2B2%5B-0.85-0.1285%20%5D%3D0%5C%5CQ_%7Bcv%7D%2B3%2B2%28-0.9785%29%3D0%5C%5CQ_%7Bcv%7D%2B3-1.957%3D0%5C%5CQ_%7Bcv%7D%2B1.04%3D0%5C%5CQ_%7Bcv%7D%3D-1.04%5C%5C)
The heat transfer rate is 1.04 Btu/s from the liquid to the surroundings.
