Nonshielded cable with a 1.5-inch diameter should have a minimum bending radius of
1 answer:
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The distance from Point A=500 mm
Explanation:
M := 40kg c := 200mm
μs := 0.3 d := 3
a := 400mm e := 4
b := 800mm
Initial guesses: := 200 N P := 50N
Plz refer to the image below
Answer:
8.24μm
Explanation:
The theory of brittle fracture was used to solve this problem.
And if you follow through with the attachment made a the subject of the formula
Such that,
a = 2x(69x10⁹)x0.3/pi(40x10⁶)²
= 4.14x10¹⁰/5.024x10¹⁵
= 8.24x10^-06
= 8.24μm
This is the the maximum length of the surface flaw
Answer:
The mechanical advantage is 3 to 1
Explanation:
A frictionless pulley with three support ropes carries equal tension on each of the ropes thus;
Tension in each pulley rope = T
Total tension in the 3 ropes = 3 × T = 3·T
Direction of the tension forces on each rope = Unidirectional
Total force provided by the 3 ropes = 3·T
Therefore, a force, T, applied at the end of the rope will result in a lifting force of 3·T
Hence, the mechanical advantage = 3·T to T which is presented as follows;
The mechanical advantage = 3 to 1.