Answer:
The value of Modulus of elasticity E = 85.33 ×

Beam deflection is = 0.15 in
Explanation:
Given data
width = 5 in
Length = 60 in
Mass of the person = 125 lb
Load = 125 × 32 = 4000
We know that moment of inertia is given as


I = 1.40625 
Deflection = 0.15 in
We know that deflection of the beam in this case is given as
Δ = 

E = 85.33 ×

This is the value of Modulus of elasticity.
Beam deflection is = 0.15 in
Answer:
(a) the velocity ratio of the machine (V.R) = 1
(b) The mechanical advantage of the machine (M.A) = 0.833
(c) The efficiency of the machine (E) = 83.3 %
Explanation:
Given;
load lifted by the pulley, L = 400 N
effort applied in lifting the, E = 480 N
distance moved by the effort, d = 5 m
(a) the velocity ratio of the machine (V.R);
since the effort applied moved downwards through a distance of d, the load will also move upwards through an equal distance 'd'.
V.R = distance moved by effort / distance moved by the load
V.R = 5/5 = 1
(b) The mechanical advantage of the machine (M.A);
M.A = L/E
M.A = 400 / 480
M.A = 0.833
(c) The efficiency of the machine (E);

Answer:
look up the assignment number. its in the left side of the screen. its what i did when i had problems.
Explanation:
You can get hurt if u don’t use it properly.