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forsale [732]
3 years ago
12

You guys are working hard on this school work... You guys deserve to take a break, come hang out with me.

Chemistry
1 answer:
Wittaler [7]3 years ago
5 0

Answer:

hggggggggggggggggggggggggggggggggggggsssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss

Explanation:

jjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj

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Number 2) According to Rutherford's model, the nucleus itself only consisted of protons. However, as we now know due to research in quantum mechanics, if this was true this would make the atom unstable due to the cycle of attraction and repulsion.
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3 years ago
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Data for the decomposition of hydrogen peroxide at some set temperature T is provided below. The rate law depends only on the co
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Answer:

0.00442 s^{-1} is the value of the rate constant.

Explanation:

2 H_2O_2\rightarrow 2 H_2O + O_2

Let the order of the reaction be x.

The rate law of the reaction can be written as:

R=k[H_2O_2]^x

1. Rate of the reaction when concentration changes from 0.882 M to 0.697 M in 0 seconds  to 60 seconds.

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0.00308 M/s=k[0.697 M]^x..[1]

2. Rate of the reaction when concentration changes from  0.697 M to 0.566 M in 240 seconds to 360 seconds.

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[1] ÷ [2]

\frac{0.00308 M/s}{0.00227 M/s}=\frac{k[0.697 M]^x}{k[0.236M]^x}

Solving fro x:

x = 0.92 ≈ 1

R=k[H_2O_2]^1

0.00308 M/s=k[0.697 M]^1

k=\frac{0.00308 M/s}{[0.697 M]^1}=0.00442 s^{-1}

0.00442 s^{-1} is the value of the rate constant.

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