The answer is B 1,500 meters since 1 kilometer to meters is 1,000 and u add the 500
Answer:
If an object accelerates from rest, with a constant acceleration of 5.4 m/s2, what will its velocity be after 28s? v0 = 0 v= ? a = 5.4 m/s2. ∆x = t = 28 s. 3.
Explanation:
<h2>Answer: 6031,9s
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The equation to calculate the period (in seconds) of a body orbiting a massive body (in this specific case a spacecraft with mass orbiting Mars) is:
(1)
Where:
is the radius of the orbit measured from the center of Mars to the satellite
is the gravity constant with a value of
is the mass of Mars, which is known to be
Now, if we are told that the spacecraft is in a low orbit near the surface of Mars, we can assume the radius of the orbit is approximately equal to the radius of Mars :
Having this stated, let’s begin with the solution:
Solving this equation being careful with the units, and taking into account we have:
Finally:
>>>>>This is the period of the orbit of the spacecraft around Mars
Answer:
The acceleration of the cart is 283.54g
Explanation:
It is given that,
Initial speed of the car, u = 35 km/h = 9.72 m/s
Finally, it stops, v = 0
Diameter of the dime, d = 1.7 cm
Let a is the acceleration of the car. Using third equation of motion to find it as :
So, the acceleration of the car is and it is decelerating.
Since,
So,
So, the acceleration of the cart is 283.54g. Hence, this is the required solution.
A "derived unit" is a specific combination of base units with its own name. <em>(3)</em>
Examples:
<u>Combination of base units</u> <u>Its own name</u>
kilogram-meter / second² Newton
Coulomb / second Ampere
kilogram-meter² / second² (Newton-meter) Joule
kilogram-meter² / second³ (Joule / sec) Watt