Answer:
The no of revolutions is 2.032 revolution.
Explanation:
Given that,
Moment of inertia = 0.85 Kgm²
Radius = 170 mm
Force = 32 N
Time = 2s
We need to calculate the angular acceleration
Using formula of torque
Where, F = force
r = radius
I = moment of inertia
Put the value into the formula
We need to calculate the rotational speed
Using equation of angular motion
We need to calculate the angular position
Using equation of angular motion
We need to calculate no of revolutions
Hence, The no of revolutions is 2.032 revolution.
Newton's 2nd law of motion:
Net Force = (mass) x (acceleration) .
The law shows the relationship among an object's mass
and acceleration, and the net force acting on it.
If you know any two of the quantities in the formula,
the law can be used to calculate the third one.
Answer: 244.05 J
Explanation:
To find speed at 30 m above the ground use equation:
V²=Vo²-2Gs
V0=31.4m/s
s=30m
G=9.81m/s²
-----------------------
V²=31.4²-2*9.81*30
V²=985.96+588.6
V²=1574.56
V=39.68m/s ---speed of arrow on 30 m obove the ground
Use equation for kinetic enrgy:
Ke=mV²/2
m=0.155kg
V=39.68m/s
-------------------------
Ke=0.155kg*(39.68m/s)²/2
Ke=0.155*1574.5/2
Ke=244.05J
Newton first law state that anything in motion or rest will remain in motion or in rest until an external force is applied
Newton third law of motion state that every action have equal and opposite reaction
Answer:
a) Δx = 180.59 m
b) T = 6001 N
Explanation:
a)
According to Newton's second law, which says that acceleration is directly proportional to the net force, the equation is equal to:
ΣF = m*a = T-f
Clearing a, and solving:
a = (T-f)/m = (T-f)/2*m = (12000-5800)/(2*700) = 4.43 m/s^2
To evaluate the final speed the following equation will be used:
vf^2 = vi^2 + 2*a*Δx = 0 + 2*a*Δx = 2*a*Δx
Clearing Δx:
Δx = vf^2/2*a = (40 m/s)^2/(2* 4.43 m/s^2) = 180.59 m
b)
The tension is equal to:
T = m*a + f = (700 kg * 4.43 m/s^2) + 2900 N = 6001 N