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3 years ago

What are the five advantages of using machine and tools in our daily life?

Physics

1 answer:

daser333 [38]3 years ago

7 0

Answer:

it makes our work easy and

time saving

it multiply our force applied

it complete our work with high efficiency

by using this,less effort is required for the work.

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HELP WILL GIVE BRAINLIEST IF CORRECT

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It’s B i literally jus learned this

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3 years ago

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A vertical spring stretches 4.0 cm when a 12-g object is hung from it. The object is replaced with a block of mass 28 g that osc

marin [14]

Answer:

Time period of the osculation will be 0.0671 sec

Explanation:

It is given a vertical spring is stretched by 4 cm

So change in length of the spring x = 4 cm = 0.04 m

Mass which is hung from it m = 12 gram = 0.012 kg

Sprig force will be equal to weight of the mass

So $kx=mg$

$k\times 0.04=0.012\times 9.8$

k = 244.7 N/m

Now new mass is m = 28 gram = 0.028 kg

So time period with new mass will be

$T=2\pi \sqrt{\frac{m}{k}}$

$=2\times 3.14 \sqrt{\frac{0.028}{244.7}}=0.0671sec$

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3 years ago

What happens to the volume of sound as the amplitude gets larger?

tino4ka555 [31]

The sound is perceived as louder if the amplifier increases, and softer if the amplitude decreases.

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3 years ago

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a plane flies from Addis Ababa to Gamble is 400km. in 2 hrs, then straight back to Gamma is 200km. in 1hrs what is the average s

kramer

Answer:

a) Average speed = 200 Km/hr

b) Average velocity = 0 m/s

c) Total distance = 800 Km

d) Total displacement = 0 Km

Explanation:

a) Let the speed of the plane from Addis Ababa to Gamble be represented by $S_{1}$ , and from Gamble to Addis Ababa by $S_{2}$ .

Average speed = $\frac{S_{1} + S_{2} }{2}$

$S_{1}$ = $\frac{distance}{time}$ = $\frac{400}{2}$

= 200 Km/hr

$S_{2}$ = $\frac{distance}{time}$ = $\frac{200}{1}$

= 200 Km/hr

Average speed = $\frac{200 + 200}{2}$

= 200 Km/hr

b) Velocity = $\frac{displacement}{time}$

Average velocity = $\frac{total displacement}{total time taken}$

Since the plane flies from Addis Ababa to Gamble, then back to Addis Ababa, its total displacement is zero.

So that,

Average velocity = 0 m/s

c) Total distance = 400 Km + 400 Km

= 800 Km

d) Total displacement = 400 Km + (-400 Km)

= 0 Km

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3 years ago

A large box of mass M is pulled across a horizontal, frictionless surface by a horizontal rope with tension T. A small box of ma

Nesterboy [21]

Answer:

T = g μ_s ( M+m )

78.4 N

Explanation:

When both of them move with the same acceleration , small box will not slip over the bigger one. When we apply force on the lower box, it starts moving with respect to lower box. So a frictional force arises on the lower box which helps it too to go ahead . The maximum value that this force can attain is mg μ_s . As a reaction of this force, another force acts on the lower box in opposite direction .

Net force on the lower box

= T - mg μ_s = M a ( a is the acceleration created by net force in M )

Considering force on the upper box

mg μ_s = ma

a = g μ_s

Put this value of a in the equation above

T - m gμ_s = M g μ_s

T = mg μ_s + M g μ_s

= g μ_s ( M+m )

2 )

Largest tension required

T = 9.8 x .50 x ( 10+6 )

= 78.4 N

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4 years ago

What are the five advantages of using machine and tools in our daily life?​

What are the five advantages of using machine and tools in our daily life?