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3 years ago

What is a variable and what do it do

2 answers:

4 0

A variable is a quantity that may change within the context of a mathematical problem or experiment. Typically, we use a single letter to represent a variable. The letters x, y, and z are common generic symbols used for variables.

Variables are used to store information to be referenced and manipulated in a computer program. They also provide a way of labeling data with a descriptive name, so our programs can be understood more clearly by the reader and ourselves. It is helpful to think of variables as containers that hold information.

frosja888 [35]3 years ago

3 0

Varuable, In algebra, a symbol (usually a letter) standing in for an unknown numerical value in an equation :)

You might be interested in

Which is the pathway of light as it travels through the eye?cornea → iris → retina → lenscornea → iris → lens → retinairis → cor

Vikki [24]

Answer:

Cornea >iris>lens >retina

Explanation:

Can't exactly figure out the answer but I think it should look like this

7 0

2 years ago

What is the osmotic pressure, in atm, of a 0.287 M solution of MgCl2 at

Flauer [41]

Answer:

Π = 21.9 atm

Explanation:

The equation used to find osmotic pressure is:

Π = iMRT

In this formula,

>> Π = osmotic pressure (atm)

>> i = van't Hoff factor

>> M = molarity (M)

>> R = constant (0.0821 atm*L/mol*K)

>> T = temperature (K)

Remember, van't Hoff factor is the amount of ions the species (MgCl₂) dissociates into while in solution. MgCl₂ dissociates into 3 ions. These ions are Mg²⁺ and 2 Cl⁻.

The temperature needs to be in Kelvin....

37.0 °C + 273.15 = 310.15 K

You now know the value of all the variables.

Π = iMRT

Π = (3)(0.287 M)(0.0821 atm*L/mol*K)(310.15 K)

Π = 21.9 atm

3 0

2 years ago

an atom of element Y has an electronic structure of 2.8.5. Would the element Y be a metal or non-metal? Explain your answer

OLEGan [10]

Answer:

non-metal

Explanation:

The element has 5 electrons on last energy level, so given element is non-metal. Most Metals have 1 or 2 electrons on the last level.

5 0

4 years ago

In the first step of the addition reaction with HBr, the pi electrons of the double bond react with the hydrogen ion, H+, produc

Andrei [34K]

Answer:

See the figure

Explanation:

In this case, we have to take into account the stability of the carbocations:

Terciary>Secundary>>Primary.

In other words, is we have the most substituted carbocation we will have more stability. Therefore in the carbocation formation, the charge would go in the most substituted carbon of the double bond for each case.

8 0

3 years ago

Consider the reaction between hcl and o2: 4hcl(g)+o2(g)→2h2o(l)+2cl2(g) when 63.1 g of hcl are allowed to react with 17.2 g of o

Roman55 [17]

The balanced chemical reaction is expressed as:

4hcl(g)+o2(g)→2h2o(l)+2cl2(g)

To determine the percent yield of the reaction, we need to calculate for the theoretical yield. This is the maximum amount of the product that can be produced from the reaction given the initial amounts of the reactants. First, we identify the limiting reactant as follows:

63.1 g of hcl ( 1 mol / 36.46 g ) ( 1 mol O2 / 4 mol HCl) ( 32 g / mol) = 13.85 g O2
17.2 g of o2 ( 1 mol / 32 g ) ( 4 mol HCl / 1 mol O2) ( 36.46 g / mol) = 78.39 g HCl

Therefore, the limiting reactant would be HCl. We use the value for the HCl to calculate for the theoretical yield.

63.1 g of hcl ( 1 mol / 36.46 g ) ( 2 mol Cl2 / 4 mol HCl) ( 70.9 g / mol ) = 61.35 g Cl2

Percent yield = actual / theoretical x 100
= 59.6 / 61.35 x 100
= 97.1%

4 0

3 years ago