Electrons and protons, but not neutrons.
Answer:
3.87 x 10^24
Explanation:
Simply multiply the moles by avogadros number
6.42 moles of H2O x 6.022 x 10^23 molecules/1 mole of H2O = 3.87 x 10^24 molecules of H2O
RbOH is a strong base that dissociates completely and HCl is a strong acid that too dissociates completely. the complete reaction between the acid and base is;
RbOH + HCl ---> RbCl + H₂O
stoichiometry of acid to base is 1:1
At neutralisation point
H⁺ mol = OH⁻ mol
mol = molarity x volume
if Ma - molarity of acid and Va - volume of acid reacted
Mb - molarity of base and Vb - volume of base reacted
Ma x Va = Mb x Vb
0.5 M x 52.8 mL = Mb x 60.0 mL
Mb = 0.44 M
molarity of base - 0.44 M
Answer:
The final volume of the balloon is = 28.11 L
Explanation:
Initial pressure
= 1.03 atm = 104.325 K pa
Initial temperature
= 26 °c = 299 K
Initial volume
= 22.4 L
Final temperature
= 22 °c = 295 K
Final pressure
= 0.81 atm = 82 K pa
We know that

Put all the values in above formula we get

= 28.11 L
This is the final volume of the balloon.