Answer : The specific heat of the metal is,
Explanation
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of metal = ?
= specific heat of water =
= mass of metal = 95.0g
= mass of water = 50.0 g
= final temperature of mixture =
= initial temperature of metal =
= initial temperature of water =
Now put all the given values in the above formula, we get
Therefore, the specific heat of the metal is,
Answer:
3 Cu + 8 HNO3 --> 3 Cu(NO3)2 + 2 NO + 4 H2O
Explanation:
Make sure both sides are equal
3 <u>Cu</u> + 8 H<u>N</u>O3 --> 3 <u>Cu</u>(NO3)2 + 2 <u>N</u>O + 4 H2O
// start by those elements that change their oxidation degree
<u>Cu</u> and <u>N</u>
// also you can write reduction-oxidation reactions
+ 2
-->
| 2
- 3
-->
| 3
// write the numbers of electrons that are lost/gained as the coefficients of the opposite elements
// then check if H and O are the same on both sides
// adjust if they aren't.