The important difference between wiring panels in series or in parallel is that electrically it affects the voltage and amperage of the resultant circuit.
In a series circuit you sum the voltage of each panel to get the overall voltage of the array. However, the amperage of the overall circuit stays the same stays the same.
Ceramics must be heated in order to harden the clay and make it durable. The tool used to heat the clay is called a Kiln.
<h3>What happens when ceramic is heated?</h3>
Cristobalite is a silica polymorph that is used in ceramics. Quartz particles in porcelain can change into cristobalite during burning. This has effects on the fired matrix's thermal expansion. When there is a high level of vitrification or a shape is unstable during the firing of ceramic ware, warping occurs.
Ceramic items are porous, brittle, and rigid. They are thus employed in the production of glass, ceramics, cement, and bricks. Additionally, ceramics are employed extensively in gas turbine engines. Artificial bones and dental implants are both made of bio-ceramics.
Any of the several tough, fragile, heat- and corrosion-resistant materials created by sculpting and then heating an inorganic, nonmetallic material like clay to a high temperature are known as ceramics.
In order to solidify the clay and make ceramics durable, heat must be applied. A kiln is the name of the device used to heat clay.
To learn more about ceramics refer to:
brainly.com/question/26247382
#SPJ4
16
if you add 9+10 you get 18 - 7+6
Answer:
471 days
Explanation:
Capacity of Carvins Cove water reservoir = 3.2 billion gallons i.e. 3.2 x 10˄9 gallons
As,
1 gallon = 0.133 cubic feet (cf)
Therefore,
Capacity of Carvins Cove water reservoir in cf = 3.2 x 10˄9 x 0.133
= 4.28 x 10˄8
Applying Mass balance i.e
Accumulation = Mass In - Mass out (Eq. 01)
Here
Mass In = 0.5 cfs
Mass out = 11 cfs
Putting values in (Eq. 01)
Accumulation = 0.5 - 11
= - 10.5 cfs
Negative accumulation shows that reservoir is depleting i.e. at a rate of 10.5 cubic feet per second.
Converting depletion of reservoir in cubic feet per hour = 10.5 x 3600
= 37,800
Converting depletion of reservoir in cubic feet per day = 37, 800 x 24
= 907,200
i.e. 907,200 cubic feet volume is being depleted in days = 1 day
1 cubic feet volume is being depleted in days = 1/907,200 day
4.28 x 10˄8 cubic feet volume will deplete in days = (4.28 x 10˄8) x 1/907,200
= 471 Days.
Hence in case of continuous drought reservoir will last for 471 days before dry-up.
