Answer:
The formula defining the photon energies that would be emitted by transitions between the hydrogen energy levels are given by the equation:
ΔE = -13.6Z²[1/n₁² - 1/n₂²]eV, where (1 eV = 1.602×10-19 Joules) and n₁ = initial energy level and n₂ = final energy level.
Z = Atomic number of the atom
Answer:C.) It has one group in which the manipulated variable is tested, and another in which the responding variable is tested
Explanation: hope this helps
Answer:
810 pm
Explanation:
Step 1: Given and required data
- Velocity of the atom (v): 490 m/s
- Mass of a hydrogen atom (m): 1.67 × 10⁻²⁷ kg
- Planck's constant (h): 6.63 × 10⁻³⁴ J.s
Step 2: Calculate the de Broglie wavelength of the hydrogen atom
We will use de Broglie's equation.
λ = h / m × v
λ = 6.63 × 10⁻³⁴ J.s / 1.67 × 10⁻²⁷ kg × 490 m/s = 8.10 × 10⁻¹⁰ m
Step 3: Convert 8.10 × 10⁻¹⁰ m to picometers
We will use the conversion factor 1 m = 10¹² pm.
8.10 × 10⁻¹⁰ m × 10¹² pm/1 m = 810 pm
.316 moles just divide by the molar mass of naoh which is 39.997. So 12.64 divived by 39.997 is .3160237. that is 3.16x10-1
The balanced chemical reaction is written as:
<span>4C(s) + S8(s) → 4CS2(l)
We are given the amount of carbon and sulfur to be used in the reaction. We need to determine first the limiting reactant to be able to solve this correctly.
</span>7.70 g C ( 1 mol / 12.01 g) =0.64 mol C
19.7 g S8 ( 1 mol / 256.48 g) = 0.08 mol S8
The limiting reactant would be S8. We use this amount to calculate.
0.08 mol S8 ( 4 mol CS2 / 1 mol S8 ) ( 256.48 g / 1 mol ) = 78.8 g CS2
