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3 years ago

All forces acting upon a body are equal in magnitude

Physics

1 answer:

Elena-2011 [213]3 years ago

8 0

Answer:

Explanation:

It's called static equilibrium. The object is motionless and every force equals/cancels each other out

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Juggles the clown stands on one end of a teeter-totter at rest on the ground. Bangles the clown jumps off a platform 2.4 m above

tester [92]

Answer:

mj = 53.3kg

Explanation:

Since both gravitational energies are the same:

Eb = Ej => mb*g*hb = mj*g*hj

Solving for mj:

mj = mb*hb/hj = 80*2.4/3.6

mj = 53.3kg

5 0

3 years ago

How far can light travel in one year?

elena-14-01-66 [18.8K]

The answer is b
300,000 km

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3 years ago

A motorcycle and rider have a total mass equal to 300 kg. The rider applies the brakes, causing the motorcycle to decelerate at

seraphim [82]

Answer:

Net force = - 1500 N

Explanation:

We calculate the net force acting using Newton's second Law:

$F_{net}=m*a\\F_{net}=(300 \,kg)*(-5\,m/s^2)\\F_{net}=-1500\,N$

5 0

3 years ago

Which one is the answer ?

ollegr [7]

It’s blurry the pic

But I think that is the second one

6 0

3 years ago

What are (a) the charge and (b) the charge density on the surface of a conducting sphere of radius 0.12 m whose potential is 230

slamgirl [31]

Answer:

(a) q=3.07 nC

(b) σ=17 nC/m²

Explanation:

Given data

Radius r=0.12m

Potential V=230 V

To find

(a) Charge q

(b) Charge density σ

Solution

For Part (a)

As we know that potential is:

$V_{potential}=k_{constat}\frac{q_{charge}}{r_{radius}} \\\\q_{charge}=\frac{V_{potential*r_{radius}}}{k_{constant}}$

Substitute the given values

$q_{charge}=\frac{(0.12m)(230V)}{9*10^{9} }\\ q_{charge}=3.07*10^{-9}C\\or\\q_{charge}=3.07nC$

For Part (b)

The charge density is given by:

σ=q/(4πr²)

Substitute the given values and value of q to find charge density

$=\frac{3.07*10^{-9}C}{4\pi (0.12m)^2}\\ =1.69*10^{-8}C/m^2\\or\\=17nC/m^2$

σ=17 nC/m²

3 0

3 years ago