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Simora [160]
2 years ago
14

Xavier is roller skating at 14 km/h and tosses a set of keys forward on the ground at 8 km/h. The speed of the keys relative to

the ground is
Physics
1 answer:
Arturiano [62]2 years ago
4 0

Answer:

22 km/h

Explanation:

Given that,

Speed of Xavier, v = 14 km/h

He tosses a set of keys forward on the ground at 8 km/h, v' = 8 km/h

We need to find the speed of the keys relative to the ground. Let it is V.

As both Xavier and the keys are moving in same diretion. The relative speed wrt ground is given by :

V = v+v'

V= 14 + 8

V = 22 km/h

So, the speed of the keys relative to the ground is 22 km/h.

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Its a very small planet
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3 years ago
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What's the time constant of a 10 H inductor and a 200 ohm resistor connected in series
melamori03 [73]
<h3>Option B</h3><h3>The time constant of a 10 H inductor and a 200 ohm resistor connected in series is 50 millisecond</h3>

<em><u>Solution:</u></em>

Given that,

10 H inductor and a 200 ohm resistor connected in series

To find: time constant

<em><u>The time constant in seconds is given as:</u></em>

Time\ constant = \frac{L}{R}

Where,

L is the inductance in henry and R is the resistance in ohms

Time\ constant = \frac{10}{200}\\\\Time\ constant = 0.05\ seconds

Convert to millisecond

1 second = 1000 millisecond

0.05 second = 0.05 x 1000 = 50 millisecond

Thus time constant is 50 millisecond

7 0
3 years ago
Railroad car A, with mass 6275 kg, is traveling east at 6.5 m/s along a straight track. It strikes railroad car B, with mass 515
LekaFEV [45]

The speed of A and B immediately after collision is 5.28m/s

<u>Explanation:</u>

Mass of A is 6275kg

Speed of A is 6.5m/s

Mass of B is 5155kg

Speed of B is 3.8m/s

Track is frictionless.

A and B stick together.

speed of attached A and B = ?

mₐsₐ + mᵇsᵇ = (mₐ + mb) s

6275 X 6.5 + 5155 X 3.8 = ( 6275 + 5155) X s\\\\s = \frac{40787.5 + 19589}{11430}\\ \\s = \frac{60376.5}{11430}\\ \\s = 5.28m/s

Therefore, The speed of A and B immediately after collision is 5.28m/s

4 0
3 years ago
I can someone help me and also I gtg so ill be back in a bit
Korvikt [17]

Answer: No sure what to do

Explanation: points for points

3 0
3 years ago
A 20 kg truck drives in a circle of radius 4 m at 10m/s. What causes
jek_recluse [69]

Answer:

Normal force

Explanation:

  • The force is centipetral force

Calculating :-

  • Mass=m=20kg
  • Radius=r=4m
  • Velocity=10m/s=v

We know

\boxed{\sf F_c=\dfrac{mv^2}{r}}

\\ \sf\longmapsto F_c=\dfrac{20(10)^2}{4}

\\ \sf\longmapsto F_c=\dfrac{20(100)}{4}

\\ \sf\longmapsto F_c=\dfrac{2000}{4}

\\ \sf\longmapsto F_c=500N

6 0
3 years ago
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