Answer:
E=1.969 × 10¹¹ Pa
Explanation:
The formula to apply is;
E=F*L/A*ΔL
where
E=Young modulus of elasticity
F=Force in newtons
L=Original length in meters,m
A=area in square meters m²
ΔL= Change in length in meters,m
Given
F= 8000 lb = 8000*4.448 =35584 N
L= 5 in = 0.127 m
A= 0.7 in² =0.0004516 m²
ΔL = 0.002 in = 5.08e-5 m
Applying the formula
E=(35584 * 0.127)/(0.0004516*5.08e-5 )
E=1.969 × 10¹¹ Pa
Answer:
The major and minor stresses are as 2060.59 psf, -310.59 psf and 1185.59 psf.
Explanation:
The major and minor principal stresses are given as follows:


Here
is the normal stress which is 1750 psf
is 0
is the shear stress which is 800 psf
So the formula becomes

Similarly, the minimum normal stress is given as

The maximum shear stress is given as

Answer:
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Explanation: