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astraxan [27]
2 years ago
15

Click this link to view O*NET’s Work Styles section for Accountants. Note that common work styles are listed toward the top and

less common work styles are listed toward the bottom. According to O*NET, what are some common work styles needed by Accountants? Select four options
trust
dependability
creativity
attention to detail
integrity
analytical thinking
Engineering
2 answers:
Tanzania [10]2 years ago
6 0

Answer:

dependability  

attention to detail

integrity

analytical thinking

Explanation:

viva [34]2 years ago
3 0

Answer:

b, d, e, f

Explanation:

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What is an isentropic process?
snow_tiger [21]

Answer: Isentropic process is the process in fluids which have a constant entropy.

Explanation: The  isentropic process is considered as the ideal thermodynamical  process and has both adiabatic as well as reversible processes in internal form.This process supports no transfer of heat and  no transformation of matter .The entropy of the provided mass also remains unchanged or consistent.These processes are usually carried out on material on  the efficient device.

5 0
3 years ago
A homeowner consumes 260 kWh of energy in July when the family is on vacation most of the time. Determine the average cost per k
Llana [10]

Answer:

16.2 cents

Explanation:

Given that a homeowner consumes 260 kWh of energy in July when the family is on vacation most of the time.

Where Base monthly charge of $10.00. First 100 kWh per month at 16 cents/kWh. Next 200 kWh per month at 10 cents/kWh. Over 300 kWh per month at 6 cents/kWh.

For the first 100 kWh:

16 cent × 100 = 1600 cents = 16 dollars

Since 1 dollar = 100 cents

For the remaining energy:

260 - 100 = 160 kwh

10 cents × 160 = 1600 cents = 16 dollars

The total cost = 10 + 16 + 16 = 42 dollars

Note that the base monthly of 10 dollars is added.

The cost of 260 kWh of energy consumption in July is 42 dollars

To determine the average cost per kWh for the month of July, divide the total cost by the total energy consumed.

That is, 42 / 260 = 0.1615 dollars

Convert it to cents by multiplying the result by 100.

0.1615 × 100 = 16.15 cents

Approximately 16.2 cents

7 0
3 years ago
Which traits are common in all four career pathways of the Information Technology field? Check all that apply.
Komok [63]

Answer:

Accuracy and attention to detail, Problem solving and critical thinking skills, Knowledge of programming language .

Explanation:

It is a technological area in which a person learns how to develop computer hardware, including PCs, laptops, tablets, processing, networking, and other hardware parts. Another field of study in IT is Management Information Systems (MIS).

The IT industry's career paths can be categorized equally in the two primary field’s hardware and software areas  

In hardware, there is Production, maintenance, research and development, and strategic planning.

In software, there is manufacturing, development, programming, software testing, and maintenance and support under software.  

Computer operations, administration of databases, sales / marketing and data centre management are connected areas.

7 0
2 years ago
Write a SELECT statement that returns the same result set as this SELECT statement. Substitute a subquery in a WHERE clause for
sergiy2304 [10]

Answer:

SELECT distinct VendorName FROM Vendors

WHERE VendorID IN (

SELECT VendorID FROM Invoices

)

Explanation:

6 0
3 years ago
Determine the following parameters for the water having quality x=0.7 at 200 kPa:
ra1l [238]

Solution :

Given :

Water have quality x = 0.7 (dryness fraction) at around pressure of 200 kPa

The phase diagram is provided below.

a). The phase is a standard mixture.

b). At pressure, p = 200 kPa, T = $T_{saturated}$

   Temperature = 120.21°C

c). Specific volume

  $v_{f}= 0.001061, \ \ v_g=0.88578 \ m^3/kg$

  $v_x=v_f+x(v_g-v_f)$

       $=0.001061+0.7(0.88578-0.001061)$

       $=0.62036 \ m^3/kg$

d). Specific energy (u_x)

    $u_f=504.5 \ kJ/kg, \ \ u_{fg}=2024.6 \ kJ/kg$

   $u_x=504.5 + 0.7(2024.6)$

         $=1921.72 \ kJ/kg$

e). Specific enthalpy $(h_x)$

   At $h_f = 504.71, \ \ h_{fg} = 2201.6$

   h_x=504.71+(0.7\times 2201.6)

        $= 2045.83 \ kJ/kg$

f). Enthalpy at m = 0.5 kg

  $H=mh_x$

       $= 0.5 \times 2045.83$

       = 1022.91 kJ

7 0
3 years ago
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