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3 years ago

A chocolate chip cookie is an example of a (2 points) a homogeneous mixture b heterogeneous mixture c suspension d colloid

Physics

2 answers:

kumpel [21]3 years ago

8 0

Answer:

I think it is heterogeneous mixture. have a good day

Soloha48 [4]3 years ago

3 0

Answer:

heterogeneous mixture

Explanation:

i took the test

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A minivan sells for 33,200 dollars. Give the price of the minivan in a) kilodollars and megadollars

amm1812

The prefix of a unit could give you a hint on its extent with respect to the base unit. In this case, the base unit is money in terms of dollars. When you say kilodollars, that would be 1,000 times as large as a dollar. Hence,

33,200 dollars * 1 kilodollar/ 1,000 dollars = 33.2 kilodollars

When you say megadollars, that would be a million times as large as a dollar. Hence,

33,200 dollars * 1 megadollar/1,000,000 dollars = 0.0332 megadollars

6 0

4 years ago

A spring with k = 53 N/m hangs vertically next to a ruler. The end of the spring is next to the 18 cm mark on the ruler. If a 2.

Anarel [89]

Answer:

1.07 m

Explanation:

x = Compression of the spring

k = Spring constant = 53 N/m

Initial length = 18 cm

P = Kinetic energy

K = Kinetic energy

At the lowest point of the mass the energy conservation is as follows

$P_{ig}+P_{is}+K_i=P_{fg}+P_{fs}+K_f\\\Rightarrow mgx+0+0=mgx+\frac{1}{2}kx^2\\\Rightarrow x=\frac{2mg}{k}\\\Rightarrow x=\frac{2\times 2.4\times 9.81}{53}\\\Rightarrow x=0.89\ m$

At its lowest position the mark on the ruler will be

$x_f=0.18+0.89\\\Rightarrow x_f=1.07\ m$

The spring line will end up at 1.07 m

4 0

3 years ago

A horizontal force of 150 N is used to push a 40.0-kg packing crate a distance of 6.00 m on a rough horizontal surface. If the c

icang [17]

Answer:

a. 900 J

b. 0.383

Explanation:

According to the question, the given data is as follows

Horizontal force = 150 N

Packing crate = 40.0 kg

Distance = 6.00 m

Based on the above information

a. The work done by the 150-N force is

$W = F x = \mu N x = \mu\ m\ g\ x$

$W = 150 \times 6$

= 900 J

b. Now the coefficient of kinetic friction between the crate and surface is

$\mu = \frac {F}{m\timesg}$

$= \frac{150}{40\times 9.8}$

= .383

We simply applied the above formulas so that each one part could calculate

3 0

4 years ago

Gasoline and propane fumes are most likely to accumulate in what part of the boat

aleksley [76]

The boat has a lot of parts that has a necessary part in order for it to move and for it to stop. But as the question above asks, the part where the gasoline and the propane fumes accumulate is in the bilge, which is one of the parts of the boat that is considered to be important.

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3 years ago

You have been working on a new, strong, lightweight ceramic which will be used to replace steel bearing balls. One cubic meter o

marin [14]

Answer:

r=2.6 cm

Explanation:

Hi!

Lets call steel material 1, and the new alloy material 2. You know their densities:

$\rho_1=8.08*10^3\frac{kq}{m^3}\\\rho_2=3.14*10^3\frac{kq}{m^3}$

The volume of a sphere with radius r is given by:

$V=\frac{4}{3}\pi r^3$

Then the masses of the bearings are:

$m_1=\rho_1V_1=\frac{4}{3}\pi r_1^3 \\m_1=\rho_2V_2=\frac{4}{3}\pi r_2^3$

For the masses to be the same:

$\rho_1 V_1 = \rho_2 V_2\\\frac{V_2}{V_1} =\frac{\rho_1}{\rho_2}\\(\frac{r_2}{r_1})^3 = \frac{8.08}{3.14}=2.57\\r_2=\sqrt[3]{2.57}\;r1 =1.37r_1=1.37*1.9cm=2.6cm$

5 0

4 years ago