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kati45 [8]
3 years ago
14

A wedge has a mechanical advantage greater than 1 because the output force of the wedge is greater than the input force. a. TRUE

b. FALSE
Engineering
2 answers:
DiKsa [7]3 years ago
5 0

Answer:

True

Explanation:

Mechanical Advantage Of A Wedge

It is the ratio of the output force to the input force. A wedge applies more force to the object (output force) than the user applies to the wedge (input force), so the mechanical advantage of a wedge is greater than 1

Nikitich [7]3 years ago
3 0
The answer is true Because the mechanical fall of the children’s in the be clear and the Johnsons because
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A thick steel sheet of area 150 in.2 is exposed to air near the ocean. After a one-year period it was found to experience a weig
Bingel [31]

Answer:

Rate of corrosion = 24.95 mpy

Rate of corrosion = 0.63 mm/yr

Explanation:

given data

steel sheet area = 150 in²

weight loss = 485 g

density of steel = 7.9 g/cm³

time taken = 1 year

to find out

rate of corrosion in (a) mpy and (b) mm/yr

solution

we get here the rate of corrosion that is express as

rate of corrosion = (k × W) ÷ (D × A × T)     ..................1

here k is constant  and w is total weight lost and t is time taken for loss and A is surface area and D is density of steel

so put her value in equation 1 we get

Rate of corrosion = \frac{534*485*1000}{7.9*150*24hr*365day/yr}

Rate of corrosion = 24.95 mpy

and

Rate of corrosion = \frac{87.6*485*1000}{7.9*150*2.54^2*24hr*365days/yr}

Rate of corrosion = 0.63 mm/yr

5 0
3 years ago
EJERCICIO 6
Ket [755]

Answer:

mnfokfnfi3or

Explanation:

can you translate it into english.....

8 0
3 years ago
A furnace uses preheated air to improve its fuel efficiency. Determine the adiabatic flame temperature when the furnance is oper
balu736 [363]

Answer:

2543 k

Explanation:

This problem can be resolved by applying the first law of thermodynamics

<u>Determine the adiabatic flame temperature</u> when the furnace is operating at a mass air-fuel ratio of 16 for air preheated to 600 K

attached below is a detailed solution

cp = 1200

8 0
3 years ago
An aluminum bar 125 mm long with a square cross section 16 mm on an edge is pulled in tension with a load of 66,700 N and experi
AfilCa [17]

Answer: the modulus of elasticity of the aluminum is 75740.37 MPa

Explanation:

Given that;

Length of Aluminum bar L = 125 mm

square cross section s = 16 mm

so area of cross section of the aluminum bar is;

A = s² = 16² = 256 mm²

Tensile load acting the bar p = 66,700 N

elongation produced Δ = 0.43

so

Δ = PL / AE

we substitute

0.43 = (66,700 × 125) / (256 × E)

0.43(256 × E) = (66,700 × 125)

110.08E = 8337500

E = 8337500 / 110.08

E = 75740.37 MPa

Therefore, the modulus of elasticity of the aluminum is 75740.37 MPa

4 0
3 years ago
While discussing run-flat tires: Technician A says that some are self-sealing tires and are designed to quickly and permanently
musickatia [10]

Answer:

The correct option is d ( Neither A nor B)

Explanation:

Technician A made 2 mistakes in his statement.Firstly the tire is self supporting not self sealing.

Secondly, this tire does not provide permanent sealing of punctured area option a is incorrect.

This self-supporting tire after being affected with complete air leakage can temporarily bear the load of the car and avoid rolling over a distance of 80 km at a maximum speed of 55 mph. Here is what technician B suggested incorrectly as the tire after being.Here the technician B suggested incorrectly as the tire after being affected with puncture can not travel at any speed so option B is wrong

Since option a and b are incorrect and c is invalid.

4 0
3 years ago
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