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Sidana [21]
3 years ago
5

Consider the reaction below Na2CO3 (aq) + CaCl2 (aq) CaCO3 (s) + 2NaCl (aq) If the releases 39.4 kJ of energy, how many kilocalo

ries does it release? (1 cal = 4.184 J) (Round off answer to 2 decimal place)​
Physics
1 answer:
denis23 [38]3 years ago
3 0

Answer: 9.42

Explanation: yes

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Aaron's normal response time to apply the car brakes is 0.7 seconds. Aaron's response time doubles when he is tired. How far wil
Likurg_2 [28]

Aaron's car is moving at speed of 30 m/s

His reaction time is given as 0.7 s

but when he is tired the reaction time is doubled

Now we need to find the distance covered by his car when he is tired during the time when he react to apply brakes

So here since during this time speed is given as constant so we can say that distance covered can be product of speed and time

So here we can use

d = v*t

d = 30 * 1.4

d = 42 m

So the car will move to 42 m during the time when he apply brakes

3 0
3 years ago
As a gaseous element condenses, the atoms become ________ and they have ________ attraction for one another.
romanna [79]

Answer:

blank 1: close together

blank 2: more

3 0
1 year ago
Im bad at work problems can any one help with this problem ?
lyudmila [28]
We will put the number of trips in the first column, the miles driven in the second column and gallons of fuel used in the third column.

8    7,680    1,010
7    9,940    1,330
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12  13,920  2,050
4 0
4 years ago
. During a collision with a wall, the velocity of a 0.200-kg ball changes from 20.0 m/s toward the wall to 12.0 m/s away from th
mixer [17]

Answer:

106.7 N

Explanation:

We can solve the problem by using the impulse theorem, which states that the product between the average force applied and the duration of the collision is equal to the change in momentum of the object:

F \Delta t = m (v-u)

where

F is the average force

\Delta t is the duration of the collision

m is the mass of the ball

v is the final velocity

u is the initial velocity

In this problem:

m = 0.200 kg

u = 20.0 m/s

v = -12.0 m/s

\Delta t = 60.0 ms = 0.06 s

Solving for F,

F=\frac{m(v-u)}{\Delta t}=\frac{(0.200 kg) (-12.0 m/s-20.0 m/s)}{0.06 s}=-106.7 N

And since we are interested in the magnitude only,

F = 106.7 N

5 0
3 years ago
Read 2 more answers
A cat climbs 10 m directly up a tree.
Harman [31]
 <span>there is no horizontal displacement if he went straight up 

straight up means vertical, so his vertical displacment is 20 m</span>
6 0
3 years ago
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