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3 years ago

Newton's second

Physics

1 answer:

Andru [333]3 years ago

4 0

Explanation:

The second law states that the greater the mass of an object, the more force it will take to accelerate the object. There is even an equation that says Force = mass x acceleration or F=ma. This also means that the harder you kick a ball the farther it will go.

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In a double slit experiment, the intensity of light at the center of the central bright fringe is measured to be 6.2 µW/m2. What

-BARSIC- [3]

Answer:

I_FWHW = 3.2 μW / m²

Explanation:

In the analysis of optics and electricity a very useful magnitude is the width at half height (FWHW) and the intensity at this height, which is given by

I_FWHW = I₀ / 2

corresponds to the width of the line for this intensity.

In this case they give the maximum intensity for which

I_FWHW = 6.2 / 2

I_FWHW = 3.2 μW / m²

You do not give more data in your exercise, but the most interesting calculation is to find the angle values for which you have this intensity since it is this range is 50% of the energy of the system, have I write the equation for this calculation

I = Io cos² x₁ (sin x / x)²

x₁ = π d sin θ /λ

x = π b sin θ /λ

where d is the separation of the slits and b the width of each slit

5 0

4 years ago

Please help Need good grade

ivann1987 [24]

Answer:

The other angle is 120°.

Explanation:

Given that,

Angle = 60

Speed = 5.0

We need to calculate the range

Using formula of range

$R=\dfrac{v^2\sin(2\theta)}{g}$ ...(I)

The range for the other angle is

$R=\dfrac{v^2\sin(2(\alpha-\theta))}{g}$ ....(II)

Here, distance and speed are same

On comparing both range

$\dfrac{v^2\sin(2\theta)}{g}=\dfrac{v^2\sin(2(\alpha-\theta))}{g}$

$\sin(2\theta)=\sin(2\times(\alpha-\theta))$

$\sin120=\sin2(\alpha-60)$

$120=2\alpha-120$

$\alpha=\dfrac{120+120}{2}$

$\alpha=120^{\circ}$

Hence, The other angle is 120°

6 0

4 years ago

A mixing blade on a food processor extends out 3 inches from its center. if the blade is turning at 600 revolutions per minute,

7nadin3 [17]

First let's convert everything into SI units.
The length of the blade is 3 inches. Keeping in mind that 1 inc=0.025 m, we have
$L=3 in \cdot 0.025 \frac{m}{inc} =0.075 m$
The angular speed is 600 revolutions per minute. Keeping in mind that $1 rev=2 \pi rad$ and $1 min=60 s$ , the angular speed becomes
$\omega = 600 \frac{rev}{min} \frac{2 \pi rad/rev}{60 s/min}=62.8 rad/s$

And so, the linear velocity of the edge of the blade is equal to
$v=\omega L=(62.8rad/s)(0.075 m)=47 m/s$

8 0

3 years ago

Read 2 more answers

A wire carrying a 32.0 A current passes between the poles of a strong magnet such that the wire is perpendicular to the magnet's

marin [14]

Answer:

2.24 T

Explanation:

From Electromagnetic Field,

F = BILsin∅................ Equation 1

Where F = Force on the wire, B = Field strength, I = current flowing in the conductor, L = length of the conductor, ∅ = The angle the conductor makes with the magnetic field.

Making B the subject of the equation,

B = F/ILsin∅..................... Equation 2

Given: F = 2.15 N, I = 32 A, L = 3.00 cm = 0.03 m, ∅ = 90° ( the wire is perpendicular to the magnetic field)

Substitute into equation 2

B = 2.15/(32×0.03×sin90°)

B = 2.15/0.96

B = 2.24 T.

Hence the Field strength = 2.24 T

7 0

4 years ago

What generates the magnetic field in a current carrying wire?

Fynjy0 [20]

The electricity causes the magnetic field. the electricity changes the magnetic waves around the wire causing the wires waves to change, creating an electro magnet

5 0

4 years ago